The mean starting salary for nurses is 67,694 dollars nationally. The standard deviation is approximately 10,333 dollars. The starting salary is not normally distributed. A sample of 30 starting salaries for nurses is taken. It is possible with rounding for a probability to be 0.0000. a) Identify the individual, variable, type of variable and the random variable X in the context of this problem. The individual is Select an answer all nurses the mean starting salary of all nurses 30 randomly selected nurses the mean starting salary of 30 randomly selected nurses the starting salary a randomly selected nurse The variable information collected from each individual is Select an answer the mean starting salary of 30 randomly selected nurses all nurses the starting salary the mean starting salary of all nurses a randomly selected nurse 30 randomly selected nurses This variable is a Select an answer qualitative -- discrete qualitative quantitative -- continuous variable. The random variable X is as follows: Select an answer rv X = the mean starting salary of 30 randomly selected nurses rv X = starting salary is normally distributed rv X = all nurses rv X = the starting salary of a randomly selected nurse rv X = a randomly selected nurse rv X = the mean starting salary of all nurses b) List the givens with the correct symbols. ? μ X n σ N X̄ s p = 67694 dollars ? s N σ n p μ X̄ X = 10333 dollars ? p X μ N n s σ X̄ = 30 c) Identify the random variable ¯¯¯XX¯ in the context of this problem. Select an answer rv X̄ = the mean starting salary of all nurses rv X̄ = the mean starting salary of 30 randomly selected nurses rv X̄ = the starting salary of 30 randomly selected nurses rv X̄ = starting salary is normally distributed rv X̄ = the starting salary of a randomly selected nurse rv X̄ = a randomly selected nurse
Contingency Table
A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.
Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
The mean starting salary for nurses is 67,694 dollars nationally. The standard deviation is approximately 10,333 dollars. The starting salary is not normally distributed. A sample of 30 starting salaries for nurses is taken.
It is possible with rounding for a probability to be 0.0000.
a) Identify the individual, variable, type of variable and the random variable X in the context of this problem.
The individual is Select an answer all nurses the mean starting salary of all nurses 30 randomly selected nurses the mean starting salary of 30 randomly selected nurses the starting salary a randomly selected nurse
The variable information collected from each individual is Select an answer the mean starting salary of 30 randomly selected nurses all nurses the starting salary the mean starting salary of all nurses a randomly selected nurse 30 randomly selected nurses
This variable is a Select an answer qualitative -- discrete qualitative quantitative -- continuous variable.
The random variable X is as follows:
Select an answer rv X = the mean starting salary of 30 randomly selected nurses rv X = starting salary is normally distributed rv X = all nurses rv X = the starting salary of a randomly selected nurse rv X = a randomly selected nurse rv X = the mean starting salary of all nurses
b) List the givens with the correct symbols.
? μ X n σ N X̄ s p = 67694 dollars
? s N σ n p μ X̄ X = 10333 dollars
? p X μ N n s σ X̄ = 30
c) Identify the random variable ¯¯¯XX¯ in the context of this problem.
Select an answer rv X̄ = the mean starting salary of all nurses rv X̄ = the mean starting salary of 30 randomly selected nurses rv X̄ = the starting salary of 30 randomly selected nurses rv X̄ = starting salary is normally distributed rv X̄ = the starting salary of a randomly selected nurse rv X̄ = a randomly selected nurse
d) Find the mean of the sampling distribution of the sample mean.
Put the numeric value in the first box and the correct units in the second box.
e) Find the standard deviation of the sampling distribution of the sample mean.
Put the numeric value rounded to two decimal places in the first box and the correct units in the second box.
f) What is the shape of the sampling distribution of the sample mean?
Select an answer uniform left-skewed right-skewed normal or approximately normal unknown
Why? Check all that apply:
- n is at least 30
- n is less than 30
- σσ is known
- population is normal
- σσ is unknown
- population is not normal
g) Find the probability that the sample mean starting salary of the 30 randomly selected nurses is less than 69836.6 dollars.
Round final answer to 4 decimal places.
h) Find the probability that the sample mean starting salary of the 30 randomly selected nurses is more than 71816.85 dollars.
Round final answer to 4 decimal places.
i) Is a mean starting salary of 71816.85 dollars unusually high for 30 randomly selected nurses?
Select an answer Yes, the probability of having a sample mean starting salary of at least 71816.85 dollars is less than or equal to 0.05 Yes, the probability of having a sample mean starting salary of at least 71816.85 dollars is more than 0.05 Yes, the probability of having a sample mean starting salary of at most 71816.85 dollars is less than or equal to 0.05 Yes, the probability of having a sample mean starting salary of at most 71816.85 dollars is more than 0.05 No, the probability of having a sample mean starting salary of at least 71816.85 dollars is less than or equal to 0.05 No, the probability of having a sample mean starting salary of at least 71816.85 dollars is more than 0.05 No, the probability of having a sample mean starting salary of at most 71816.85 dollars is less than or equal to 0.05 No, the probability of having a sample mean starting salary of at most 71816.85 dollars is more than 0.05
j) If you found a mean starting salary for a sample of 30 nurses as high as 71816.85 dollars, what might you conclude?
There is evidence that the mean starting salary of all nurses may now be higher than 67694 dollars There is no evidence that the mean starting salary of all nurses has changed from 67694 dollars There is evidence that the mean starting salary of all nurses may now be lower than 67694 dollars
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
