The mean of a normal distribution of scores is 90 and s = 5. The percentage of area between 90 and 95 is       a. 34%     b. 50%     c. 68%     d. 95%

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  1. The mean of a normal distribution of scores is 90 and s = 5. The percentage of area between 90 and 95 is

     

       

    a. 34%

       

    b. 50%

       

    c. 68%

       

    d. 95%

Expert Solution
Step 1

Given information-

Population mean, µ = 90

Standard deviation, s = 5

Let, X be the random variable which is normally distributed.

We have to find the percentage of area between 90 and 95.

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