The mean number of days that the Monarch Butterfly spends in its larval stage is 14.1 days, with a standard deviation of 2.2 days. This distribution is approximately Normal. What is the z-score for an individual butterfly that spends 12.7 days in its larval stage? - 0.64 O 0.64 O 6.29 0.74 O 0.26

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**Question:**

The mean number of days that the Monarch Butterfly spends in its larval stage is 14.1 days, with a standard deviation of 2.2 days. This distribution is approximately Normal. What is the z-score for an individual butterfly that spends 12.7 days in its larval stage?

**Options:**

- ○ -0.64
- ○ 0.64
- ○ 6.29
- ○ 0.74
- ○ 0.26

**Explanation:**

To find the z-score, use the formula:

\[ z = \frac{(X - \text{mean})}{\text{standard deviation}} \]

Where:
- \( X \) is the individual value (12.7 days),
- Mean is 14.1 days,
- Standard deviation is 2.2 days.

Plugging these values into the formula gives:

\[ z = \frac{(12.7 - 14.1)}{2.2} = \frac{-1.4}{2.2} \approx -0.64 \]

Thus, the z-score is approximately -0.64.
Transcribed Image Text:**Question:** The mean number of days that the Monarch Butterfly spends in its larval stage is 14.1 days, with a standard deviation of 2.2 days. This distribution is approximately Normal. What is the z-score for an individual butterfly that spends 12.7 days in its larval stage? **Options:** - ○ -0.64 - ○ 0.64 - ○ 6.29 - ○ 0.74 - ○ 0.26 **Explanation:** To find the z-score, use the formula: \[ z = \frac{(X - \text{mean})}{\text{standard deviation}} \] Where: - \( X \) is the individual value (12.7 days), - Mean is 14.1 days, - Standard deviation is 2.2 days. Plugging these values into the formula gives: \[ z = \frac{(12.7 - 14.1)}{2.2} = \frac{-1.4}{2.2} \approx -0.64 \] Thus, the z-score is approximately -0.64.
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