The mean number of credits earned by students is claimed to be 30.0. A random sample is taken to test if the mean is different. The sample has x = 31.2 s= 2.1, and n= Use this data to solve problems 7 through 11. 40. %3D The stem and leaf plot below shows the running times in a 400 m run for a random sample of 19 runners. 6|0 represents 60 seconds. Use this data for questions 18 through 21. 5|89 6|01558 7|0246689 8|12335 For a one sample t-test with sample size 58, the degrees of freedom is: 58 O b. 59 a. O c. 57

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The mean number of credits earned by students is claimed to be 30.0. A random sample
is taken to test if the mean is different. The sample has x = 31.2 s= 2.1, and n= 40.
%3D
Use this data to solve problems 7 through 11.
The stem and leaf plot below shows the running times in a 400 m run for a random
sample of 19 runners. 6|0 represents 60 seconds. Use this data for questions 18
through 21.
5|89
6|01558
7|0246689
8|12335
For a one samplet-test with sample size 58, the degrees of freedom is:
а. 58
O b. 59
О с. 57
Transcribed Image Text:The mean number of credits earned by students is claimed to be 30.0. A random sample is taken to test if the mean is different. The sample has x = 31.2 s= 2.1, and n= 40. %3D Use this data to solve problems 7 through 11. The stem and leaf plot below shows the running times in a 400 m run for a random sample of 19 runners. 6|0 represents 60 seconds. Use this data for questions 18 through 21. 5|89 6|01558 7|0246689 8|12335 For a one samplet-test with sample size 58, the degrees of freedom is: а. 58 O b. 59 О с. 57
The estimate of the standard error of the sampling distribution is
based on the previous question.
O a. 0.3320
O b. 0.0525
С. 2.1
Ос.
Transcribed Image Text:The estimate of the standard error of the sampling distribution is based on the previous question. O a. 0.3320 O b. 0.0525 С. 2.1 Ос.
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