The mean hemoglobin level in the blood for a certain large group of individuals is 21.0 grams per milliliter (g/ml). The standard deviation is 2 g/ml. If a sample of 25 individuals is selected, find the probability that the mean will be greater than 21.3 g/ml. Assume that the variable is normally distributed.

Q: Assume the random variable X is normally distributed with mean u = 50 and standard deviation o = 7.…

A: Let X be the random variable which follows normal distribution with mean 50 and standard deviation…

Q: Assume that the scores of a college entry exam are normally distributed with a mean of 400 and a…

A: Given,mean(μ)=400standard deviation(σ)=60

Q: Assume that the readings on the thermometers are normally distributed with a mean of 0°C and a…

A: We have given that,  X be the random variable from standard normal distribution with mean (μ) = 0°C…

Q: In the United States, the mean birth weight for boys is 3.41 kg, with a standard deviation of 0.55…

A: From the given information, the  mean birth weight for boys is 3.41 kg and the standard deviation is…

Q: The lifetime of a certain type of t.v tube has a normal distribution with a mean of 80.0 and a…

A: Given Data: Let X represent the random variable   Mean=80 SD=6   X~ Normal (80, 62)

Q: The phooysoical fitness of an athlete is often measured by how much oxygen the athlete takes in…

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A:

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A:

Q: Assume that adults have IQ scores that are normally distributed with μ=38 and a standard deviation…

A:

Q: Assume that a randomly selected subject is given a bone density test. those test scores are normally…

A:

Q: Assume that a randomly selected subject is given a bone density test. those test scores are normally…

A: Let X be the random variable from standard normal distribution with mean (μ) = 0 standard deviation…

Q: Find the probability that 1 man has weight greater than 160 lb. Assume that weights of males are…

A: Let X represent the random variable Mean=182.9 SD=40.8   X~ Normal (182.9, 40.82)

Q: The mean number of milligrams of sodium in a certain brand of dinner is 540mg with a standard…

A: Given Mean=540 Standard deviations=48 Sample size=64

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: A randomly selected subject is given a bone density test and the test scores are normally…

Q: Assume that adults have IQ scores that are normally distributed with μ=105 and a standard deviation…

A: Assume that adults have IQ scores that are normally distributed with μ=105 and a standard deviation…

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: Obtain the probability of a bone density test score greater than –1.52. The probability of a bone…

Q: Total plasma volume is important in determining the required plasma component in blood replacement…

A: From the information, given thatwhere, denotes the sample meandenotes the population standard…

Q: A distribution of values is normal with a mean of 189.6 and a standard deviation of 68.6. Find the…

A: Refer to Standard normal table/Z-table to find the probability of z= 1.5.ORUse excel formula…

Q: Find the probability given a test score greater than - 1.82 and draw a sketch of the region

A: It is given that  Mean, μ = 0 Standard deviation, σ = 1 Z-Score, Z = ( X - μ )/σ

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: Given Those test scores are normally distributed with a mean of 0 and a standard deviation of 1.

Q: A distribution of values is normal with a mean of 235 and a standard deviation of 14.4. Find P63,…

A:

Q: Assume the random variable X is normally distributed with mean u = 50 and standard deviation o = 7.…

A: Given,μ=50σ=7Find 96th percentile?

Q: Assume that the distribution of residuals is approximately normal with mean 0c m and standard…

A:

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: The test scores are -1.64 and 1.64.

Q: Find the probability that a dinner has 600mg or more sodium. 0.00380.0038 0.10560.1056…

A: It is given that  Mean, μ = 540 Standard deviation, σ = 48 Z-Score, Z = ( X - μ )/σ

Q: A vertical line drawn through a normal distribution at z = -0.72 separates the distribution into two…

A: Given :  A vertical line drawn through a normal distribution at z = -0.72 separates the distribution…

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: Let Z be the random variable from standard normal distribution with mean = 0 and standard deviation…

Q: A vertical line drawn through a normal distribution at z = +1.10 separates the distribution into two…

A: The value of Z ~N(0,1) , and is usually represented as, Z=X-μσ Now, using this form, a Z-table is…

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: It is given that the test scores follow normal distribution with mean 0 and the standard deviation…

Q: Assume that a randomly selected subject given a bone density test. Those test scores are normally…

A:

Q: The average age of our class is 22.3 years.  The standard deviation is 4.7 years.  If the variable…

A: Let X: Age of student. X~N(μ=22.2, σ=4.7)

Q: Assume that scores on a bone density test are normally distributed with a mean of 0 and a deviation…

A: It follows normal distribution with mean 0 and standard deviation 1for a randomly selected subject,…

Q: he weight of a green forest frog has a normal distribution with mean 150.3 g and a standard…

A: given data,normal distribution μ=150.3σ=5we have to find out the probabilty for the given data

Q: Assume that the heights of a population of adults form a normal distribution with a mean µ =69…

A: It is known that, there are 12 inches in 1 foot.The provided information are:

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: Obtain the probability that a given score is less than z = –0.55. The probability that a given score…

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A:

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: Given information Mean µ = 0 Standard deviation σ = 1

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: Answer:- Given, Bone density test scores (X) are normally distributed with a mean of 0 and a…

Q: The physical fitness of an athlete is often measured by how much oxygen the athlete takes in (which…

A: Obtain the probability that an elite athlete has a maximum oxygen uptake of at least 93.07 ml/kg.…

Q: The physical fitness of an athlete is often measured by how much oxygen the athlete takes in (which…

A: The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the mean…

Q: Thermometers used at the Tongas National Park in Alaska are supposed to give readings of 0° C at the…

A: Given that, μ=0σ=1 By using the standard normal table, P(Z>z) = 2%  1-P(Z<z) = 0.02P(Z<z) =…

Q: The physical fitness of an athlete is often measured by how much oxygen the athlete takes in (which…

A: Let X is the mean maximum oxygen uptake which is normally distributed. Given: mean=μ=65.5standard…

Q: Assume that a randomly selected subject is given a bone density test. Those test scores are normally…

A: From the given information, Test scores that is X is normally distributed woth mean 0 and standard…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.