The mean cost of a five pound bag of shrimp is 50 dollars with a standard deviation of 6 dollars. If a sample of 40 bags of shrimp is randomly selected, what is the probability that the sample mean would be less than 51.3 dollars? Round your answer to four decimal places.

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**Problem Statement:**

The mean cost of a five-pound bag of shrimp is $50, with a standard deviation of $6.

If a sample of 40 bags of shrimp is randomly selected, what is the probability that the sample mean would be less than $51.3? Round your answer to four decimal places.

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Transcribed Image Text:**Problem Statement:** The mean cost of a five-pound bag of shrimp is $50, with a standard deviation of $6. If a sample of 40 bags of shrimp is randomly selected, what is the probability that the sample mean would be less than $51.3? Round your answer to four decimal places. **Answer Box:** - [How to enter your answer (opens in new window)](link) **Tools Provided:** - Tables - Keypad - Keyboard Shortcuts
This table is a Standard Normal Distribution table, which provides values representing the area to the left of a given Z-score. The Z-score is represented in the leftmost column (Z) with decimal precision to the first digit. Across the top, there are columns labeled from .00 to .09, which further refine the Z-score to two decimal places.

### Explanation:

- **Z-Score column**: Each row begins with a Z-score, from -3.9 to 0.0. This score represents standard deviations away from the mean in a standard normal distribution.

- **Columns .00 to .09**: These headers represent the hundredths place in the Z-score. For example, a Z-score of -1.38 would require looking at the row labeled -1.3 and then across the column under .08.

- **Values**: Every intersection of a row and column gives the cumulative probability from the far left up to that Z-score. For example, a Z-score of -1.38 gives a cumulative probability of 0.08379, meaning approximately 8.379% of the data falls to the left of this value in a standard normal distribution.

### Highlighted Values:

- Specific Z-scores and their respective cumulative areas, such as -1.4 with an area of 0.08076 and -1.3 with an area of 0.08379, are marked for quicker reference, signifying important or commonly referenced values.

This table is essential in statistics for converting Z-scores to percentiles in a standard normal distribution, helping to determine probabilities and areas under the curve.
Transcribed Image Text:This table is a Standard Normal Distribution table, which provides values representing the area to the left of a given Z-score. The Z-score is represented in the leftmost column (Z) with decimal precision to the first digit. Across the top, there are columns labeled from .00 to .09, which further refine the Z-score to two decimal places. ### Explanation: - **Z-Score column**: Each row begins with a Z-score, from -3.9 to 0.0. This score represents standard deviations away from the mean in a standard normal distribution. - **Columns .00 to .09**: These headers represent the hundredths place in the Z-score. For example, a Z-score of -1.38 would require looking at the row labeled -1.3 and then across the column under .08. - **Values**: Every intersection of a row and column gives the cumulative probability from the far left up to that Z-score. For example, a Z-score of -1.38 gives a cumulative probability of 0.08379, meaning approximately 8.379% of the data falls to the left of this value in a standard normal distribution. ### Highlighted Values: - Specific Z-scores and their respective cumulative areas, such as -1.4 with an area of 0.08076 and -1.3 with an area of 0.08379, are marked for quicker reference, signifying important or commonly referenced values. This table is essential in statistics for converting Z-scores to percentiles in a standard normal distribution, helping to determine probabilities and areas under the curve.
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