The mean cholesterol levels of women age 45-59 in Ghana, Nigeria, and Seychelles is 5.1 mmol/l and the standard deviation is 1.0 mmol/l. Assume that cholesterol levels are normally distributed and a random sample of 21 women are selected. It is possible with rounding for a probability to be 0.0000. a) Identify the individual, variable, type of variable and the random variable X in the context of this problem. The individual is Select an answer The variable information collected from each individual is Select an answer This variable is a Select an answer v variable. The random variable X is as follows: Select an answer b) List the givens with the correct symbols. ? v = 5.1 mmol/l ? v = 1 mmol/l = 21 c) Identify the random variable X in the context of this problem. Select an answer d) Find the mean of the sampling distribution of the sample mean. Put the numeric value in the first box and the correct units in the second box.

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The mean cholesterol levels of women age 45-59 in Ghana, Nigeria, and Seychelles is 5.1 mmol/l and the standard
deviation is 1.0 mmol/l. Assume that cholesterol levels are normally distributed and a random sample of 21
women are selected.
It is possible with rounding for a probability to be 0.0000.
a) Identify the individual, variable, type of variable and the random variable X in the context of this problem.
The individual is
Select an answer
The variable information collected from each individual is
Select an answer
This variable is a Select an answer
variable.
The random variable X is as follows:
Select an answer
b) List the givens with the correct symbols.
= 5.1 mmol/I
? v = 1 mmol/l
? v = 21
c) Identify the random variable X in the context of this problem.
Select an answer
d) Find the mean of the sampling distribution of the sample mean.
Put the numeric value in the first box and the correct units in the second box.
Transcribed Image Text:The mean cholesterol levels of women age 45-59 in Ghana, Nigeria, and Seychelles is 5.1 mmol/l and the standard deviation is 1.0 mmol/l. Assume that cholesterol levels are normally distributed and a random sample of 21 women are selected. It is possible with rounding for a probability to be 0.0000. a) Identify the individual, variable, type of variable and the random variable X in the context of this problem. The individual is Select an answer The variable information collected from each individual is Select an answer This variable is a Select an answer variable. The random variable X is as follows: Select an answer b) List the givens with the correct symbols. = 5.1 mmol/I ? v = 1 mmol/l ? v = 21 c) Identify the random variable X in the context of this problem. Select an answer d) Find the mean of the sampling distribution of the sample mean. Put the numeric value in the first box and the correct units in the second box.
e) Find the standard deviation of the sampling distribution of the sample mean.
Put the numeric value rounded to two decimal places in the first box and the correct units in the second box.
f) What is the shape of the sampling distribution of the sample mean?
Select an answer
Why? Check all that apply:
On is at least 30
Do is unknown
population is normal
Oo is known
On is less than 30
U population is not normal
g) Find the probability that the sample mean cholesterol level of the 21 randomly selected women age 45-59 in
Ghana, Nigeria, and Seychelles is less than 5 mmol/l.
Round final answer to 4 decimal places.
DO NOT use the rounded standard deviation from part e in this computation.
Use the EXACT value of the standard deviation with the square root.
Transcribed Image Text:e) Find the standard deviation of the sampling distribution of the sample mean. Put the numeric value rounded to two decimal places in the first box and the correct units in the second box. f) What is the shape of the sampling distribution of the sample mean? Select an answer Why? Check all that apply: On is at least 30 Do is unknown population is normal Oo is known On is less than 30 U population is not normal g) Find the probability that the sample mean cholesterol level of the 21 randomly selected women age 45-59 in Ghana, Nigeria, and Seychelles is less than 5 mmol/l. Round final answer to 4 decimal places. DO NOT use the rounded standard deviation from part e in this computation. Use the EXACT value of the standard deviation with the square root.
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