The mean cholesterol levels of women age 45-59 in Ghana, Nigeria, and Seychelles is 5.1 mmol/l and the standard deviation is 1.0 mmol/l. Assume that cholesterol levels are normally distributed and a random sample of 21 women are selected.
The mean cholesterol levels of women age 45-59 in Ghana, Nigeria, and Seychelles is 5.1 mmol/l and the standard deviation is 1.0 mmol/l. Assume that cholesterol levels are normally distributed and a random sample of 21 women are selected.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:h) Find the probability that the sample mean cholesterol level of the 21 randomly selected women age 45-
59 in Ghana, Nigeria, and Seychelles is more than 5.54 mmol/l.
Round final answer to 4 decimal places.
DO NOT use the rounded standard deviation from part e in this computation.
Use the EXACT value of the standard deviation with the square root.
i) Is a mean cholesterol level of 5.54 mmol/l unusually high for 21 randomly selected women age 45-59 in
Ghana, Nigeria, and Seychelles?
Select an answer
j) If you found a mean cholesterol level for a sample of 21 women age 45-59 in Ghana, Nigeria, and
Seychelles as high as 5.54 mmol/l, what might you conclude?
Select an answer

Transcribed Image Text:d) Find the mean of the sampling distribution of the sample mean.
Put the numeric value in the first box and the correct units in the second box.
e) Find the standard deviation of the sampling distribution of the sample mean.
Put the numeric value rounded to two decimal places in the first box and the correct units in the second
box.
f) What is the shape of the sampling distribution of the sample mean?
Select an answer
Why? Check all that apply:
population is normal
o is unknown
In is less than 30
population is not normal
In is at least 30
o is known
g) Find the probability that the sample mean cholesterol level of the 21 randomly selected women age 45-
59 in Ghana, Nigeria, and Seychelles is less than 4.7 mmol/l.
Round final answer to 4 decimal places.
DO NOT use the rounded standard deviation from part e in this computation.
Use the EXACT value of the standard deviation with the square root.
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