The matrix A= 2 0 -1 4 1 -5 07 0 has eigenvalue A₁ = 1 with eigenvector ₁ = A2 = 2 of multiplicity 2 with eigenvector v2 = 2, so Ag has defect one. Use 2 to make a generalized eigenvector v3: -8. A and eigenvalue . All other eigenvectors for 1 are scalar multiples of

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A: -2=c1,-5=c2Explanation:Step 1: Step 2: Step 3: Step 4: