The matrix A = 1 3 3 -3 -5 -3 has eigenvalues X = 1 and X 3 3 1 Show that A is diagonalizable. = -2.
The matrix A = 1 3 3 -3 -5 -3 has eigenvalues X = 1 and X 3 3 1 Show that A is diagonalizable. = -2.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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this is one question with 2 part, after give answer plesae give a proof
![1
3
-3 -5 -3 has eigenvalues
3
3
1
Show that A is diagonalizable.
The matrix A =
If TV → V is diagonalizable, show that V
=
1 and λ = -2.
Null T Range T.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1d5e88e6-b1af-4aea-9b08-2dadd85f5e2c%2F2fda435b-f2a5-44f9-a273-67f1df7b5631%2Fxk901dw_processed.png&w=3840&q=75)
Transcribed Image Text:1
3
-3 -5 -3 has eigenvalues
3
3
1
Show that A is diagonalizable.
The matrix A =
If TV → V is diagonalizable, show that V
=
1 and λ = -2.
Null T Range T.
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