The mass spectrum of CóH6Br is shown below. • Explain the two peaks at 156 and 158 m/z. Predict the MF (molecular formula) for this compound. 100 - MS-NW-1589 80 20 25 50 75 100 125 150 175 m/z Relative Intensity

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**Mass Spectrum Interpretation: C₆H₆Br**

The mass spectrum of C₆H₆Br (bromobenzene) is shown below.

**Analysis Objectives:**
- **Explain the two peaks at 156 and 158 m/z.**
- **Predict the MF (molecular formula) for this compound.**

**Graph Explanation:**
The accompanying graph presents a mass spectrum, which is a plot of relative intensity versus the mass-to-charge ratio (m/z). The x-axis represents the m/z values, while the y-axis is labeled "Relative Intensity", showing the abundance of detected ions.

Key observations:
1. There are two prominent peaks at m/z values of 156 and 158.
2. The peak at m/z 156 is slightly less intense than the peak at m/z 158.

### Interpreting Significant Peaks:
- **Peaks at 156 and 158 m/z:**
  The presence of two peaks at 156 and 158 m/z with nearly equal intensity is indicative of the isotropic nature of bromine (Br). Bromine has two stable isotopes: ^79Br and ^81Br, which occur in nearly equal natural abundance (~50% each). 

  In the mass spectrometric analysis:
  - The peak at m/z 156 corresponds to the molecular ion containing the ^79Br isotope.
  - The peak at m/z 158 corresponds to the molecular ion containing the ^81Br isotope.

### Predicting Molecular Formula:
Given that the peaks correspond to the isotopes of bromine and the molecular formula is specified as C₆H₆Br, we can further verify:
- Carbon (C) has an atomic mass approximately 12.
- Hydrogen (H) has an atomic mass approximately 1. 
- Bromine (Br) isotopes have masses 79 and 81.

Calculation:
  For C₆H₆ ^79Br: 
    (6 * 12) + (6 * 1) + 79 = 156,
  For C₆H₆ ^81Br: 
    (6 * 12) + (6 * 1) + 81 = 158.

Thus, the mass spectrum confirms the molecular formula as C₆H₆Br.

This analysis includes the identification of the isotopic pattern typical for compounds containing bromine and reinforces the molecular structure of bromobenzene.
Transcribed Image Text:**Mass Spectrum Interpretation: C₆H₆Br** The mass spectrum of C₆H₆Br (bromobenzene) is shown below. **Analysis Objectives:** - **Explain the two peaks at 156 and 158 m/z.** - **Predict the MF (molecular formula) for this compound.** **Graph Explanation:** The accompanying graph presents a mass spectrum, which is a plot of relative intensity versus the mass-to-charge ratio (m/z). The x-axis represents the m/z values, while the y-axis is labeled "Relative Intensity", showing the abundance of detected ions. Key observations: 1. There are two prominent peaks at m/z values of 156 and 158. 2. The peak at m/z 156 is slightly less intense than the peak at m/z 158. ### Interpreting Significant Peaks: - **Peaks at 156 and 158 m/z:** The presence of two peaks at 156 and 158 m/z with nearly equal intensity is indicative of the isotropic nature of bromine (Br). Bromine has two stable isotopes: ^79Br and ^81Br, which occur in nearly equal natural abundance (~50% each). In the mass spectrometric analysis: - The peak at m/z 156 corresponds to the molecular ion containing the ^79Br isotope. - The peak at m/z 158 corresponds to the molecular ion containing the ^81Br isotope. ### Predicting Molecular Formula: Given that the peaks correspond to the isotopes of bromine and the molecular formula is specified as C₆H₆Br, we can further verify: - Carbon (C) has an atomic mass approximately 12. - Hydrogen (H) has an atomic mass approximately 1. - Bromine (Br) isotopes have masses 79 and 81. Calculation: For C₆H₆ ^79Br: (6 * 12) + (6 * 1) + 79 = 156, For C₆H₆ ^81Br: (6 * 12) + (6 * 1) + 81 = 158. Thus, the mass spectrum confirms the molecular formula as C₆H₆Br. This analysis includes the identification of the isotopic pattern typical for compounds containing bromine and reinforces the molecular structure of bromobenzene.
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