The mass percentage of chloride ion in a 25.00-ml sample of seawater was determined by titrating the sample with silver nitrate, precipitating silver chloride. It took 42.58 mL of 0.2997 M silver nitrate solution to reach the equivalence point in the titration. What is the mass percentage of chloride ion in sea water if its density i s 1.025 g/mL?

Q: A 0.861 g mixture containing only sodium chloride and potassium chloride was dissolved in water. It…

A: Well, we will first determine the number of moles of Cl- present in the mixture. As moles of AgNO3…

Q: A 0.702 g0.702 g mixture containing only sodium chloride and potassium chloride was dissolved in…

A: First calculate mole of each substance by dividing molar mass to the mass then calculate mole of…

Q: Iron(II) can be oxidized to iron(III) by dichromate ion, which is reduced to chromium(III) in acid…

A: From given  Initially with the data , the reaction is given and from the reaction number of moles of…

Q: Volume mL

A:

Q: What volume of 0.100 M Na3PO4 is required to precipitate all the lead(II) ions from 400.0 mL of…

A: The question is based on the concept of molarity. molarity is a method of expressing concentration…

Q: 7.) A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stocksolution. They…

A: Molar mass of Co(NO3)2 is 183 g/mol Hence moles of Co(NO3)2 taken = mass / molar mass = 5 / 183 =…

Q: If 31.4g of NaOH (MM= f Fi 40.00 g/mol) are added to 500.0 mL volumetric flask, and water is added…

A: Answer: To find out the molar concentration of NaOH, first of all we will find out its number of…

Q: What volume of 0.100 M  Na3PO4 is required to precipitate all the lead(II) ions from 200.0 mL of…

A: The required reaction is        3 Pb2+(aq) + 2 PO43- (aq) ---------> Pb3(PO4)2 (s)

Q: Solid potassium phosphate is slowly added to 125 mL of a 0.489 M lead nitrite solution until the…

A: Given: Concentration of lead phosphate = 1×10-54

Q: 7.65 g sample of an aqueous solution of hydroiodic acid contains an unknown amount of the acid. If…

A: Weight of sample=7.65g Volume=24.1mL  Concentration of barium hydraxide=0.550M

Q: A student wishes to determine the mass percentage of barium in a 2.016g sample. The student…

A: Given : Mass of sample = 2.016g Molarity of H2SO4 = 0.20M Volume of H2SO4 = 20ml

Q: O CHEMICAL REACTIONS Determining the volume of base needed to titrate a given mass... A chemistry…

A:

Q: Solid ammonium chromate is slowly added to 175 mL of a 0.397 M calcium nitrite solution until the…

A: Given: Concentration of CrO42- = 0.0543 M Concentration of calcium nitrite = 0.397 M Volume of…

Q: a student will be preparing 100.0 ml of a 0.050 m aqueous solution of NaCl in a clean and dry…

A:

Q: Solid ammonium sulfite is slowly added to 150 mL of a 0.140 M silver fluoride solution until the…

A:

Q: A student finds that it takes 46.16 mL of 0.2915 M NaOH to titrate 20.00 mL of sulfuric acid…

A: The reaction between Sulfuric acid (H2SO4) and Sodium hydroxide(NaOH) is given as:H2SO4 + 2 NaOH →…

Q: 0.946 L). (b) How many milliliters of the muriatic acid solution contain 9.66 g of HC1?

A:

Q: When aqueous solutions of sodium hydroxide and iron (II) nitrate are mixed, a red gelatinous…

A:

Q: Suppose 50.0 mL of 0.250 M CoCl2 solution is added to 25.0 mL of 0.350 M NiCl2 solution. calculate…

A: The number of moles for a given compound or a molecule refers to the ratio of its mass to the…

Q: In the laboratory a student combines 46.1 mL of a 0.375 M silver acetate solution with 16.1 mL of a…

A: The objective of the question is to find the final concentration of acetate anion when a silver…

Q: What mass of Na2 CrO4 is required to precipitate all of the silver ions from 55.0 mL of a 0.100 M…

A: Given: molarity of AgNO3 solution = 0.100 M  volume of AgNO3 solution = 55.0 mL  To calculate :…

Q: 185 mL sample of 1.20 M Pb(NO₃)₂ is mixed with 61.5 mL of 1.50 M NaCl, and the PbCl₂ precipitate is…

A: Lead nitrate reacts with sodium chloride to form lead chloride and sodium nitrate. Write the…

Q: What volume of 0.100 M NAOH is required to precipitate all of the nickel (II) ions from 150.0 mL of…

A: Reaction for the above query will be :  2NaOH(aq) + Ni(NO3)2 (aq) ------> 2NaNO3(aq) + Ni(OH)2(s)…

Q: A 185.0 mL sample of 1.200 M Pb(NO3)2 is mixed with 99.50 mL of 1.500 M NaCl and the PbCl2…

A: Concentration of Pb(NO3)2 = 1.200 MVolume of sample of Pb(NO3)2 = 185 mLConcentration of NaCl =…

Q: 18.0 g of a lead containg sample was dissolved water and an excess of sodium sulfate was added to…

A: Given data,Mass of lead sample=18.0gMass of PbSO4=308.88mg=0.30888g

Q: concentrated

A: Dear student I have given answer to your question in the image format.

Q: if 25.0ml of 0.104 m bacl solutions is pipetted into 100. ml volumetric flask and water added to the…

A: Given data => Intial volume = 25mL = V1 Intial concentration = 0.104m = M1 Final volume = 100mL =…

Q: Solid sodium hydroxide is slowly added to 125 mL of a 0.148 M manganese(II) bromide solution until…

A: Volume of manganese(II) bromide solution = 125 mLConcentration of manganese(II) bromide solution =…

Q: at a certain temperature,1.85 grams of barium hydroxide will dissolve to form 100.0 ml of a…

A: The given mass of barium hydroxide = 1.85 g The volume the solution = 100.0 mL = 0.100 L  The…

Q: A 13.3 g sample of an aqueous solution of hydrochloric acid contains an unknown amount of the acid.…

A: Given: Mass of sample = 13.3 g Volume of Ba(OH)2 = 21.1 mL Molarity of Ba(OH)2 = 0.603 M Molar mass…

Q: Solid sodium carbonate is slowly added to 125 mL of a 0.106 M calcium acetate solution until the…

A: Given : volume of calcium acetate solution = 125 mL = 0.125 L                                      (…

Q: 12.8 mL of 0.0354 M potassium permanganate solution is used to titrate 0.188 g of an unknown sample…

A: Given -> Volume of KMnO4 = 12.8 ml = 0.0128 L (1L = 1000ml) Molarity of KMnO4 = 0.0354 M Weight…

Q: Solid sodium carbonate is slowly added to 175 mL of a 0.457 M iron (II) chloride solution until the…

A:

Q: A student weighs out a 3.79 g sample of potassium nitrate, transfers it to a 250 mL volumetric…

A: Given, mass of KNO3 = 3.79 g. Volume of the solution = 250 mL = 250 mL×1 L1000 mL = 0.25 L. We have…