C5.6 m3.4 m11hị3.1 m4.1 m12h2h2L203X152X14.3ShapeSteelA992 Gr. 50DGage of AnglesIBE75 mmg1T+75 mmg2Bolt26mmBolt Diameter, dpoltb70 mmA=aspaceBspace70 mmd60 mmCspace90 тmdspace=111,75 mmespace90 тmfapace圈I|||I||| totoae 1 fg2The mass of the block that can be attached at point E so that the angle indicated (excel) is adequate for member BE. The shorter side of the angle is bolted. Find the weight for ASD,

Answer Let us first calculate the force in member BE Since there is no horizontal force acting on…

Answered: The mass of the block that can be…

The mass of the block that can be attached at point E so that the angle indicated (excel) is adequate for member BE. The shorter side of the angle is bolted. Find the weight for ASD,

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

C
5.6 m
3.4 m
11
hị
3.1 m
4.1 m
12
h2
h2
L203X152X14.3
Shape
Steel
A992 Gr. 50
D
Gage of Angles
IB
E
75 mm
g1
T+
75 mm
g2
Bolt
26
mm
Bolt Diameter, dpolt
b
70 mm
A
=
aspace
Bspace
70 mm
d
60 mm
Cspace
90 тm
dspace
=
11
1,
75 mm
espace
90 тm
fapace
圈
I|||
I|||

to
to
a
e 1 f
g2
The mass of the block that can be attached at point E so that the angle indicated (excel) is adequate for member BE. The shorter side of the angle is bolted. Find the weight for ASD,

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