The mapping approach that converts a full binary tree to a vector can be used to store generic trees, but in an inefficient manner. The method is to reserve enough space to keep the lowest, rightmost leaf and to keep null references in nodes that are not currently in use. What is the smallest possible Vector length required to store an n-element binary tree?

The mapping approach that converts a full binary tree to a vector can be used to store generic trees, but in an inefficient manner. The method is to reserve enough space to keep the lowest, rightmost leaf and to keep null references in nodes that are not currently in use. What is the smallest possible Vector length required to store an n-element binary tree?

Similar questions

Implement an algorithm to delete a node in the middle (i.e., any node butthe first and last node, not necessarily the exact middle) of a singly linked list, given only access tothat node.EXAMPLElnput:the node c from the linked list a->b->c->d->e->fResult: nothing is returned, but the new linked list looks like a ->b->d->e->f
The following code implementation for an inorder traversal has a "visit" function as a parameter. I do not know how it works and what ways it plays a role in the traversal of the linked list in a binary tree.
Define an iterative function named reverse, with one linked list argument; it returns a reference to the first node in a linked (no new LN objects) with all the values in their reverse order. This method mutates the arguments list. Do not make any new LN objects. For example, for the list l1 = LN(1, LN(2, LN 3), reverse(l1) would return LN(3, LN(2, LN 1). def reverse(l: LN) -> LN:
A set is a container that stores a collection of sorted unique elements. When we use a sorted linked structure to implement Set ADT, the time complexity of find(x), insert(x) and remove(x) are all O(n). Group of answer choices True False
IN JAVA LANGUAGE ALL INFORMATION IN PICTURES FIND MIN OF A BST CALL ON A RECURSIVE FINDMIN_R THAT WILL RETURN THE SMALLEST ELEMENT IN A BST THANK YOU!!!!!!!!!!!
In this problem, we need to create a method capable of calculating the distance between the deepest node on the left to the deepest node on the right. However my code is struggling to even output my binary search tree, and I am not sure how to code the method. Can someone please explain how I could code this?/////////////////////////////////////////////////////////////////////////// // // Pro3105 // // Write a program that creates a binary search tree of 15 to 30 // random Capital Letters. // // Define the tree width operation by writing the method that will // calculate the distance from the deepest node of the left subtree // to the deepest node of the right subtree. // // K // ......../ \.......................... // / \ // H U // .../ \..... ......./ \... // /…
In Java, Complete the incomplete method of ExpressionTree.java. The incomplete methods are private Node parsePrefix(Scanner input) // Required public void parseInfix(String string) // Optional public void parsePostfix(String string) // Optional Implementations of parseInfix and parsePostfix require use of a stack. Implementation of parsePrefix does not. Read all of the ExpressionTree.java file before starting your implementation, so that you see the helper methods that are provided and get an idea of the context for your implementation. Although not needed for your implementation, you should be sure you understand how the toStringPrefix, toStringInfix, and toStringPostfix methods work. Note: The main() method accepts a single String as its argument. The String should be a prefix, infix, or postfix mathematical expression with no characters other than operators (+, -, *, and /) and operands (single characters a-z). As written, the main() method calls parsePrefix() to create an…
When presenting a menu option to the user in the main cpp file. Asking user to input in an ID, how do I code a search method implementation where it takes that ID and search it in the binary tree and either return true if found and false if not. I am trying to steer away from using item which is attached to both (ID, username). I am trying to only take the ID input and the node pointer and traversing through the binary tree to find if the ID matches any of the nodes.
Don't skip
Given that we discovered a circular array implementation for queues to be favorable, does this suggest we would find a circularly-linked list to be similarly advantageous? Why should I/shouldn't l?