The manufacturer of the X-15 steel-belted radial truck tire claims that the mean mileage the tire can be driven before the tread wears out is 60,000 miles. Assume the mileage wear follows the normal distribution and the standard deviation of the distribution is 5,000 miles. Crosset Truck Company bought 48 tires and found that the mean mileage for its trucks is 59,500 miles. Crosset would like to know if their experience is different from the manufacturer's claim. a. State the null hypothesis and the alternate hypothesis. HO: H1: u b. State whether the decision rule is true or false: Reject H, if z<-1.96 or z> 1.96 using a 0.05 significance level. True O False c. Compute the value of the test statistic. (Negetive emount should be indicated by a minus sign. Round your answer to 3 decimal places.)

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The manufacturer of the X-15 steel-belted radial truck tire claims that the mean mileage the tire can be driven before the tread wears
out is 60,000 miles. Assume the mileage wear follows the normal distribution and the standard deviation of the distribution is 5,000
miles. Crosset Truck Company bought 48 tires and found that the mean mileage for its trucks is 59,500 miles. Crosset would like to
know if their experience is different from the manufacturer's claim.
a. State the null hypothesis and the alternate hypothesis.
HO: U
H1: p
b. State whether the decision rule is true or false: Reject H, if z<-1.96 or z> 1.96 using a 0.05 significance level.
True
False
c. Compute the value of the test statistic. (Negetive emount should be indicated by a minus sign. Round your answer to 3 decimal
places.)
Transcribed Image Text:The manufacturer of the X-15 steel-belted radial truck tire claims that the mean mileage the tire can be driven before the tread wears out is 60,000 miles. Assume the mileage wear follows the normal distribution and the standard deviation of the distribution is 5,000 miles. Crosset Truck Company bought 48 tires and found that the mean mileage for its trucks is 59,500 miles. Crosset would like to know if their experience is different from the manufacturer's claim. a. State the null hypothesis and the alternate hypothesis. HO: U H1: p b. State whether the decision rule is true or false: Reject H, if z<-1.96 or z> 1.96 using a 0.05 significance level. True False c. Compute the value of the test statistic. (Negetive emount should be indicated by a minus sign. Round your answer to 3 decimal places.)
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