The man at the window wishes to throw the 30 kg sack on the ground. To do this he allows it to swing from rest at B to point C, when he releases the cord at 0 = 30°. Determine the speed at which it strikes the ground. Conservation of A Mechanical Energy B 8m Kg + Ug = Kp + U, 8 m 0 + (16)(30)(9.8) = (0.5)(30)v,² + 0 Vo? = (16)(30)(9.8) / (0.5)(30) 16 m Vo = 17.7 m/s Note that the tension in the cord does no work on the sack because it is always perpendicular to the displacement! R 0 2007 by RC Htbeier To be published by Peason Prentice Hal Peason Education, Inc, Upper Sadde River. New Jeey All ights reseved
The man at the window wishes to throw the 30 kg sack on the ground. To do this he allows it to swing from rest at B to point C, when he releases the cord at 0 = 30°. Determine the speed at which it strikes the ground. Conservation of A Mechanical Energy B 8m Kg + Ug = Kp + U, 8 m 0 + (16)(30)(9.8) = (0.5)(30)v,² + 0 Vo? = (16)(30)(9.8) / (0.5)(30) 16 m Vo = 17.7 m/s Note that the tension in the cord does no work on the sack because it is always perpendicular to the displacement! R 0 2007 by RC Htbeier To be published by Peason Prentice Hal Peason Education, Inc, Upper Sadde River. New Jeey All ights reseved
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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where dos the 0.5 come from?
Transcribed Image Text:Example on Conservation of Mechanical Energy
The man at the window wishes to throw the 30 kg sack on the
ground. To do this he allows it to swing from rest at B to point
C, when he releases the cord at 0 = 30°. Determine the speed
at which it strikes the ground.
Conservation of
Mechanical Energy
В
8 m
Kg + UB = Kp + Up
%3D
8 m
0 + (16)(30)(9.8) = (0.5)(30)v,² + 0
Vo? = (16)(30)(9.8) / (0.5)(30)
Vo = 17.7 m/s
16 m
Note that the tension in the
cord does no work on the
\D
sack because it is always
perpendicular to the
displacement!
0 2007 by R.C. Htbeier. To be published by Pearson Prentice Hal, Pearson Education, Inc, Upper Sadde River New Jersey All rights reserved
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