The magnitude of the net force exerted in the x direction on a 2.10-kg particle varies in time as shown in the figure below. F (N) 4 3 A 2 1 1 2 3 0 4 5 (a) Find the impulse of the force over the 5.00-s time interval. I=12 XN S t (s) (b) Find the final velocity the particle attains if it is originally at rest. V=3.076 X m/s avg (c) Find its final velocity if its original velocity is -2.30 î m/s. Vf -0.024 = X m/s (d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s. F₁ 2.4 = XN

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The magnitude of the net force exerted in the x direction on a 2.10-kg particle varies in time as shown in the figure below.
F (N)
4
3
2
1
1
2 3 4
(a) Find the impulse of the force over the 5.00-s time interval.
I = 12
X N.s
t (s)
(b) Find the final velocity the particle attains if it is originally at rest.
√₁² 3.076
=
avg
=
(c) Find its final velocity if its original velocity is -2.30 î m/s.
7₁ -0.024
=
X m/s
(d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s.
F
2.4
X m/s
XN
Transcribed Image Text:The magnitude of the net force exerted in the x direction on a 2.10-kg particle varies in time as shown in the figure below. F (N) 4 3 2 1 1 2 3 4 (a) Find the impulse of the force over the 5.00-s time interval. I = 12 X N.s t (s) (b) Find the final velocity the particle attains if it is originally at rest. √₁² 3.076 = avg = (c) Find its final velocity if its original velocity is -2.30 î m/s. 7₁ -0.024 = X m/s (d) Find the average force exerted on the particle for the time interval between 0 and 5.00 s. F 2.4 X m/s XN
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