The magnetic field generated by an indefinite straight wire, with radius and crossed by a current lof uniform density on the section, is at the distance a/2from the wire axis. OB = μl/(4πа2²) OB = μl/(4πa) OB=1/(2a) OB=μla/4

icon
Related questions
Question
Please solve asap and explain how you reached that solution properly. Thank you in advance!
The magnetic field generated by an indefinite straight wire, with radius aand crossed by a current lof uniform density on the section, is at
the distance a/2from the wire axis.
OB = μl/(4πа2²)
OB = μl/(4πа)
OB=1/(2a)
OB=la/4T
Transcribed Image Text:The magnetic field generated by an indefinite straight wire, with radius aand crossed by a current lof uniform density on the section, is at the distance a/2from the wire axis. OB = μl/(4πа2²) OB = μl/(4πа) OB=1/(2a) OB=la/4T
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer