The machine element shown is fabricated from steel. The density of steel is 7850 kg/m³. Determine the mass moments of inertia (in kg-m²) of the assembly with respect to the y-axis AND the centroidal axis parallel to the y-axis. Create a table (or tables) to solve this problem.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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### Problem 2
The machine element shown is fabricated from steel. The density of steel is \( 7850 \, \text{kg/m}^3 \).

**Determine the mass moments of inertia (in kg-m²) of the assembly with respect to the \( y \)-axis AND the centroidal axis parallel to the \( y \)-axis.**

Create a table (or tables) to solve this problem.

**Dimensions:**
- \( a = 30 \, \text{mm} \)
- \( b = 70 \, \text{mm} \)
- \( c = 20 \, \text{mm} \)
- \( d = 40 \, \text{mm} \)
- \( e = 60 \, \text{mm} \)

**Diagram Description:**
The provided diagram is an isometric view of a two-part machine element:
1. **Cylindrical Section**: There is a large, horizontal main cylinder represented by a blue 3D shape.
   - Radius: \( b = 70 \, \text{mm} \)
   - Height: \( e = 60 \, \text{mm} \)

2. **Vertical Rod**: A smaller cylinder (rod) is mounted perpendicularly through the center of the larger cylinder.
   - Radius: \( c = 20 \, \text{mm} \)
   - Height: \( a = 30 \, \text{mm} \)

### Step-by-Step Solution Strategy:
1. **Calculate the volume of each part**.
   - For the larger cylinder: \( V_{\text{large}} = \pi b^2 e \)
   - For the smaller cylinder: \( V_{\text{small}} = \pi c^2 a \)

2. **Determine the masses** by multiplying the volume by the density of steel (7850 kg/m³), while ensuring conversion from mm³ to m³ is correctly handled.

3. **Determine the mass moment of inertia**:
   - Use the standard mass moment of inertia formulas for cylindrical bodies around a specific axis:
     - For a cylinder around its central vertical axis, \( I_y = \frac{1}{2} m r^2 \)
     - For a cylinder around its diameter, \( I_z = \frac{m}{4}(r^2 + \frac{h^2}{3
Transcribed Image Text:### Problem 2 The machine element shown is fabricated from steel. The density of steel is \( 7850 \, \text{kg/m}^3 \). **Determine the mass moments of inertia (in kg-m²) of the assembly with respect to the \( y \)-axis AND the centroidal axis parallel to the \( y \)-axis.** Create a table (or tables) to solve this problem. **Dimensions:** - \( a = 30 \, \text{mm} \) - \( b = 70 \, \text{mm} \) - \( c = 20 \, \text{mm} \) - \( d = 40 \, \text{mm} \) - \( e = 60 \, \text{mm} \) **Diagram Description:** The provided diagram is an isometric view of a two-part machine element: 1. **Cylindrical Section**: There is a large, horizontal main cylinder represented by a blue 3D shape. - Radius: \( b = 70 \, \text{mm} \) - Height: \( e = 60 \, \text{mm} \) 2. **Vertical Rod**: A smaller cylinder (rod) is mounted perpendicularly through the center of the larger cylinder. - Radius: \( c = 20 \, \text{mm} \) - Height: \( a = 30 \, \text{mm} \) ### Step-by-Step Solution Strategy: 1. **Calculate the volume of each part**. - For the larger cylinder: \( V_{\text{large}} = \pi b^2 e \) - For the smaller cylinder: \( V_{\text{small}} = \pi c^2 a \) 2. **Determine the masses** by multiplying the volume by the density of steel (7850 kg/m³), while ensuring conversion from mm³ to m³ is correctly handled. 3. **Determine the mass moment of inertia**: - Use the standard mass moment of inertia formulas for cylindrical bodies around a specific axis: - For a cylinder around its central vertical axis, \( I_y = \frac{1}{2} m r^2 \) - For a cylinder around its diameter, \( I_z = \frac{m}{4}(r^2 + \frac{h^2}{3
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