The Lucas numbers satisfy the recurrence relation Ln=Ln-1+ Ln-2, and the initial conditions are Lo = 2 and 4₁ = 1. Click and drag statements to find an explicit formula for the Lucas numbers. L₁ = α₂ -a for some constants a, and a₂. The recurrence relation L₁= L-1 + L₂-2 has characteristic equation 1+√√5 2+7-1=0. Its roots are >= - L-a(1+√³)* + a₂ (1-√³) 1+√√5 1-√√5 L₁ = 2 for some constants a, and a₂. 1+√ 4- (1+³)+(1-³). L₁=2 and L₁=1-a₁=1 and a₂ = 1. L₂ = 4-(+)-(-). L₁= 2 and L₁ = 1 → a₁ = 1 and ₂ = 1. L = The recurrence relation L=L+L2 has characteristic equation 1+√5 2 2-1=0. Its roots are >=
The Lucas numbers satisfy the recurrence relation Ln=Ln-1+ Ln-2, and the initial conditions are Lo = 2 and 4₁ = 1. Click and drag statements to find an explicit formula for the Lucas numbers. L₁ = α₂ -a for some constants a, and a₂. The recurrence relation L₁= L-1 + L₂-2 has characteristic equation 1+√√5 2+7-1=0. Its roots are >= - L-a(1+√³)* + a₂ (1-√³) 1+√√5 1-√√5 L₁ = 2 for some constants a, and a₂. 1+√ 4- (1+³)+(1-³). L₁=2 and L₁=1-a₁=1 and a₂ = 1. L₂ = 4-(+)-(-). L₁= 2 and L₁ = 1 → a₁ = 1 and ₂ = 1. L = The recurrence relation L=L+L2 has characteristic equation 1+√5 2 2-1=0. Its roots are >=
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter7: Distance And Approximation
Section7.1: Inner Product Spaces
Problem 42EQ
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