The local anesthetic ethyl chloride ( C2H5Cl, MM 64.51 g/mol) can be prepared by the reaction of ethylene (C2H4, MM 28.05 g/mol) with HCl (MM 36.46 g/mol), according to the balanced equation, C2H4 + HCl → C2H5Cl If 8.00 g of ethylene and 12.0 g of HCl are used, how many grams of the product are formed? Group of answer choices 18.4 g 3.48 g 21.2 g 6.78 g
The local anesthetic ethyl chloride ( C2H5Cl, MM 64.51 g/mol) can be prepared by the reaction of ethylene (C2H4, MM 28.05 g/mol) with HCl (MM 36.46 g/mol), according to the balanced equation, C2H4 + HCl → C2H5Cl If 8.00 g of ethylene and 12.0 g of HCl are used, how many grams of the product are formed? Group of answer choices 18.4 g 3.48 g 21.2 g 6.78 g
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The local anesthetic ethyl chloride ( C2H5Cl, MM 64.51 g/mol) can be prepared by the reaction of ethylene (C2H4, MM 28.05 g/mol) with HCl (MM 36.46 g/mol), according to the balanced equation,
C2H4 + HCl → C2H5Cl
If 8.00 g of ethylene and 12.0 g of HCl are used, how many grams of the product are formed?
Group of answer choices
18.4 g
3.48 g
21.2 g
6.78 g
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