Homework Help is Here – Start Your Trial Now!
Engineering
Electrical Engineering
The load at a certain factory consists of the following: 10 kW, pf = 0.6 lagging 15 kW, rf = 0.5 lagging 25 kVA, pf = 0.75 lagging 15 kVAR, pf = 0.8 lagging 22 kW 5 kVAR, pure inductance Total True Power = 85.75 kW Total Reactive Power = 58.5295 kVAr Total Apparent Power = 103.8208 KVA 1. The power factor is to be corrected to 0.95 lagging. If resistive heating units were used instead, determine the real power rating of these devices. Ans = 92.3222 2. The power factor is to be corrected to 0.95 lagging. If a synchronous motor is to be used instead, determine the real power rating of this motor if its

The load at a certain factory consists of the following: 10 kW, pf = 0.6 lagging 15 kW, rf = 0.5 lagging 25 kVA, pf = 0.75 lagging 15 kVAR, pf = 0.8 lagging 22 kW 5 kVAR, pure inductance Total True Power = 85.75 kW Total Reactive Power = 58.5295 kVAr Total Apparent Power = 103.8208 KVA 1. The power factor is to be corrected to 0.95 lagging. If resistive heating units were used instead, determine the real power rating of these devices. Ans = 92.3222 2. The power factor is to be corrected to 0.95 lagging. If a synchronous motor is to be used instead, determine the real power rating of this motor if its

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
See similar textbooks
icon
Related questions
icon
Concept explainers
Question

The load at a certain factory consists of the following:
10 kW, pf = 0.6 lagging
15 kW, rf = 0.5 lagging
25 kVA, pf = 0.75 lagging
15 kVAR, pf = 0.8 lagging
22 kW
5 kVAR, pure inductance

Total True Power = 85.75 kW
Total Reactive Power = 58.5295 kVAr
Total Apparent Power = 103.8208 KVA

1. The power factor is to be corrected to 0.95 lagging. If resistive heating units were used instead, determine the real power rating of these devices. Ans = 92.3222
2. The power factor is to be corrected to 0.95 lagging. If a synchronous motor is to be used instead, determine the real power rating of this motor if its power factor is 0.6 leading. Ans = 18.257

Expert Solution
steps

Step by step

Solved in 5 steps with 5 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Synchronous Motor
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,
SEE MORE TEXTBOOKS