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the llowing about the graph of rational functi T(X), determine whic of the following could be the function. x-intercept (,0) y-intercept (0, 1) Vertical Asymptote : x = = 1 Horizontal Asymptote : y = 3 Hole: (3,4) f(x) = O f (x) - O f(x) = f(x) = (3x-1)(x-3) (x-3)(x-1) (3x-1)(x-3) (x-3) (3x-1) (3x-1) (x+3) (x+3)(x-1) (3x+1)(x-3) (x-3)(x-1)

the llowing about the graph of rational functi T(X), determine whic of the following could be the function. x-intercept (,0) y-intercept (0, 1) Vertical Asymptote : x = = 1 Horizontal Asymptote : y = 3 Hole: (3,4) f(x) = O f (x) - O f(x) = f(x) = (3x-1)(x-3) (x-3)(x-1) (3x-1)(x-3) (x-3) (3x-1) (3x-1) (x+3) (x+3)(x-1) (3x+1)(x-3) (x-3)(x-1)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the following information about the graph of rational function \( f(x) \), determine which of the following could be the function. - \( x\text{-intercept} \left( \frac{1}{3}, 0 \right) \) - \( y\text{-intercept} (0, 1) \) - \( \text{Vertical Asymptote} : x = 1 \) - \( \text{Horizontal Asymptote} : y = 3 \) - \( \text{Hole} : (3, 4) \) ### Function Options: 1. \( \bigcirc \) \( f(x) = \frac{(3x-1)(x-3)}{(x-3)(x-1)} \) 2. \( \bigcirc \) \( f(x) = \frac{(3x-1)(x-3)}{(x-3)(3x-1)} \) 3. \( \bigcirc \) \( f(x) = \frac{(3x-1)(x+3)}{(x+3)(x-1)} \) 4. \( \bigcirc \) \( f(x) = \frac{(3x+1)(x-3)}{(x-3)(x-1)} \) The correct answer, highlighted with a filled circle, is: 1. \( \bigodot \) \( f(x) = \frac{(3x-1)(x-3)}{(x-3)(x-1)} \)
Transcribed Image Text:Given the following information about the graph of rational function \( f(x) \), determine which of the following could be the function. - \( x\text{-intercept} \left( \frac{1}{3}, 0 \right) \) - \( y\text{-intercept} (0, 1) \) - \( \text{Vertical Asymptote} : x = 1 \) - \( \text{Horizontal Asymptote} : y = 3 \) - \( \text{Hole} : (3, 4) \) ### Function Options: 1. \( \bigcirc \) \( f(x) = \frac{(3x-1)(x-3)}{(x-3)(x-1)} \) 2. \( \bigcirc \) \( f(x) = \frac{(3x-1)(x-3)}{(x-3)(3x-1)} \) 3. \( \bigcirc \) \( f(x) = \frac{(3x-1)(x+3)}{(x+3)(x-1)} \) 4. \( \bigcirc \) \( f(x) = \frac{(3x+1)(x-3)}{(x-3)(x-1)} \) The correct answer, highlighted with a filled circle, is: 1. \( \bigodot \) \( f(x) = \frac{(3x-1)(x-3)}{(x-3)(x-1)} \)
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