The lithium concentration in serum taken from a patient being treated with lithium for manic-depressive illness was analyzed using flame emission spectroscopy. A sample of the serum gave a reading of 276 units for the intensity of the 671 nm red emission line. Then, 1.00 mL of a 10.8 mM lithium standard was added to 9.00 mL of serum. This spiked serum gave an intensity reading of 621 units at the 671 nm emission line. What is the original concentration of Li* in the serum? [Li*] = mM
The lithium concentration in serum taken from a patient being treated with lithium for manic-depressive illness was analyzed using flame emission spectroscopy. A sample of the serum gave a reading of 276 units for the intensity of the 671 nm red emission line. Then, 1.00 mL of a 10.8 mM lithium standard was added to 9.00 mL of serum. This spiked serum gave an intensity reading of 621 units at the 671 nm emission line. What is the original concentration of Li* in the serum? [Li*] = mM
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The lithium concentration in serum taken from a patient being treated with lithium for manic-depressive illness was analyzed using flame emission spectroscopy. A sample of the serum gave a reading of 276 units for the intensity of the 671 nm red emission line. Then, 1.00 mL of a 10.8 mM lithium standard was added to 9.00 mL of serum. This spiked serum gave an intensity reading of 621 units at the 671 nm emission line. What is the original concentration of Li+ in the serum?
![The intensity of the serum signal is proportional to the lithium concentration in
the serum
Ix = k[Lirum]
where k is a proportionality constant.
The signal intensity of the spiked serum sample is proportional to the lithium
concentration in the spiked serum
Vo
Ix+s = k ([Lia] x + [Lirum) x
where V,/V and Vo/V are the dilution factors for the standard and the serum
respectively in the spiked sample.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd8a6cb0a-f2f4-43a1-80d9-3a0c13488518%2Fa17683b3-2ff5-4001-856c-bd5c7676f4ea%2F2pdwfsh_processed.png&w=3840&q=75)
Transcribed Image Text:The intensity of the serum signal is proportional to the lithium concentration in
the serum
Ix = k[Lirum]
where k is a proportionality constant.
The signal intensity of the spiked serum sample is proportional to the lithium
concentration in the spiked serum
Vo
Ix+s = k ([Lia] x + [Lirum) x
where V,/V and Vo/V are the dilution factors for the standard and the serum
respectively in the spiked sample.
![The lithium concentration in serum taken from a patient being treated with lithium for manic-depressive illness was
analyzed using flame emission spectroscopy. A sample of the serum gave a reading of 276 units for the intensity of the 671
nm red emission line. Then, 1.00 mL of a 10.8 mM lithium standard was added to 9.00 mL of serum. This spiked serum
gave an intensity reading of 621 units at the 671 nm emission line. What is the original concentration of Li* in the serum?
[Li*] =
mM](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd8a6cb0a-f2f4-43a1-80d9-3a0c13488518%2Fa17683b3-2ff5-4001-856c-bd5c7676f4ea%2F6hrniv_processed.png&w=3840&q=75)
Transcribed Image Text:The lithium concentration in serum taken from a patient being treated with lithium for manic-depressive illness was
analyzed using flame emission spectroscopy. A sample of the serum gave a reading of 276 units for the intensity of the 671
nm red emission line. Then, 1.00 mL of a 10.8 mM lithium standard was added to 9.00 mL of serum. This spiked serum
gave an intensity reading of 621 units at the 671 nm emission line. What is the original concentration of Li* in the serum?
[Li*] =
mM
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