The link in figure 2.14, is subjected to two forces. Determine the components (F, & F,) of each force. Ans: F 1x 519.62N → ;F1y 300N ↑ Ans: F2x 282.84N + ;F2y = 282.84N ↑ %3D F2 = 400 N F, = = 600 N 45° 30°

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Transcribed Image Text:A. Proving Instruction: The answers on edch problem are already given. Just prove the following exercises by show ing the COMPLETE, CLEAN & CORRECT SOLUTION. Make sure that your solution results to the final dnswer.
1. The link in figure 2.14, is subjected to two forces. Determine the components
(F, & F,) of each force.
Ans: F 1x
519.62N → ;F1y= 300 ↑
Ans: F2x
= 282.84N -
;F2y
282.84N ↑
F2 = 400 N
F1 = 600 N
45°
30°
Figure 2.14
Transcribed Image Text:1. The link in figure 2.14, is subjected to two forces. Determine the components (F, & F,) of each force. Ans: F 1x 519.62N → ;F1y= 300 ↑ Ans: F2x = 282.84N - ;F2y 282.84N ↑ F2 = 400 N F1 = 600 N 45° 30° Figure 2.14
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