The lines whose equations are y = 3x + 1 and y = -3x – 2 are perpendicular because the product of their slopes, and -3, respectively, is –1. a. Use a graphing utility to graph the equations in a [-10, 10, 1] by [-10, 10, 1] viewing rectangle. Do the lines appear to be perpendicular? b. Now use the zoom square feature of your utility. Describe what happens to the graphs. Explain why this is so.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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The lines whose equations are y = 3x + 1 and y = -3x – 2
are perpendicular because the product of their slopes, and
-3, respectively, is –1.
a. Use a graphing utility to graph the equations in a
[-10, 10, 1] by [-10, 10, 1] viewing rectangle. Do the lines
appear to be perpendicular?
b. Now use the zoom square feature of your utility.
Describe what happens to the graphs. Explain why this
is so.
Transcribed Image Text:The lines whose equations are y = 3x + 1 and y = -3x – 2 are perpendicular because the product of their slopes, and -3, respectively, is –1. a. Use a graphing utility to graph the equations in a [-10, 10, 1] by [-10, 10, 1] viewing rectangle. Do the lines appear to be perpendicular? b. Now use the zoom square feature of your utility. Describe what happens to the graphs. Explain why this is so.
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