The system x' = 4y + 10x² - 39x + 34, y' = 4xy + 3x - 14, has a critical point at (2, 1). The change of variables u = x - 2, v = y (-| A help (matrices) 1 brings the critical point to the origin. Then the linearization in terms of u and u is:
The system x' = 4y + 10x² - 39x + 34, y' = 4xy + 3x - 14, has a critical point at (2, 1). The change of variables u = x - 2, v = y (-| A help (matrices) 1 brings the critical point to the origin. Then the linearization in terms of u and u is:
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![The system
x' = 4y + 10x²
y = 4xy + 3x - 14,
has a critical point at (2, 1). The change of variables u = x - 2, v = y 1 brings the critical point to the origin. Then the linearization in terms of u and u is:
M-|
[]
39x + 34,
help (matrices)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5ea01508-f9b6-4a19-b038-56e12c298daf%2F392b6810-c3f1-44f1-939b-f45034cce3e8%2F28slo99_processed.png&w=3840&q=75)
Transcribed Image Text:The system
x' = 4y + 10x²
y = 4xy + 3x - 14,
has a critical point at (2, 1). The change of variables u = x - 2, v = y 1 brings the critical point to the origin. Then the linearization in terms of u and u is:
M-|
[]
39x + 34,
help (matrices)
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The linear system in matrix form is incorrect...I'm sorry but I don't know how to solve this, if you could give me any help that would be appreciated
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