The linear system below has a unique solution. By row reducing all the way to RREF (that is, no back-substitution), find that unique solution. 4.x3 12.x3 4.x1 + 24x2 + 26x3 -x1 X2 + -12 X1 3.x2 24 - - -18 X1 = + X2 = X3 =
The linear system below has a unique solution. By row reducing all the way to RREF (that is, no back-substitution), find that unique solution. 4.x3 12.x3 4.x1 + 24x2 + 26x3 -x1 X2 + -12 X1 3.x2 24 - - -18 X1 = + X2 = X3 =
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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
Transcribed Image Text:The linear system below has a unique solution. By row reducing all
the way to RREF (that is, no back-substitution), find that unique
solution.
-12
4.x3
12.x3
-x1
X2 +
3.x2
24
-
-
4.x1 + 24x2 + 26x3 =
-18
X1 =
X2 =
X3 =
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