The line that passes through the point (4, -2,0) and parallel to the vector (1, 2, –3) has symmetric equation . Check all that applies. y +2 4 = -3 O x – 1 = 4 – 2y, z = -3 O 6x – 24 = 3y + 6 = -2z %3D O x - 1 y - 2 4 , 2 = -3 -2
The line that passes through the point (4, -2,0) and parallel to the vector (1, 2, –3) has symmetric equation . Check all that applies. y +2 4 = -3 O x – 1 = 4 – 2y, z = -3 O 6x – 24 = 3y + 6 = -2z %3D O x - 1 y - 2 4 , 2 = -3 -2
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![The line that passes through the point (4, –2, 0) and parallel to the vector (1, 2, -3) has
symmetric equation _. Check all that applies.
y + 2
x – 4 =
2
||
3
x – 1 = 4 – 2y, z = -3
6x
24 = 3y + 6
-2z
-
1
y – 2
4
E- = z
-2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2aebd16f-78e6-4100-9f15-97188cb08ae2%2F77786870-ce23-4897-963e-d576f8456267%2F685ltsf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The line that passes through the point (4, –2, 0) and parallel to the vector (1, 2, -3) has
symmetric equation _. Check all that applies.
y + 2
x – 4 =
2
||
3
x – 1 = 4 – 2y, z = -3
6x
24 = 3y + 6
-2z
-
1
y – 2
4
E- = z
-2
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