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The line of intersection of II : 4x – 3y + z – 2 = 0 and - Пу : 2а + 5у — 32 + 4 — 0 is z – 2 %3D -1 O (14x – 14) = 14y = (-14z + 28) 2 y + 2 14 -7 14 o 14x – 14 -7z + 14 - = y = 14 7

The line of intersection of II : 4x – 3y + z – 2 = 0 and - Пу : 2а + 5у — 32 + 4 — 0 is z – 2 %3D -1 O (14x – 14) = 14y = (-14z + 28) 2 y + 2 14 -7 14 o 14x – 14 -7z + 14 - = y = 14 7

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The line of intersection of II : 4x – 3y + z – 2 = 0 and - Пу : 2а + 5у — 32 + 4 — 0 is z – 2 %3D -1 O (14x – 14) = 14y = (-14z + 28) 2 y + 2 14 -7 14 o 14x – 14 -7z + 14 - = y = 14 7
Transcribed Image Text:The line of intersection of II : 4x – 3y + z – 2 = 0 and - Пу : 2а + 5у — 32 + 4 — 0 is z – 2 %3D -1 O (14x – 14) = 14y = (-14z + 28) 2 y + 2 14 -7 14 o 14x – 14 -7z + 14 - = y = 14 7
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