Answered: The line of action of the 5490-lb force… | bartleby

Related questions

Question

The line of action of the 5490-lb force runs through the points A and B as shown in the figure. Determine the x and y scalar components
of F.
y, m
1
B (14, 10)
F = 5490 lb
A (-13,-4)
Answers:
Fx=
i
Fy
i
1
--x, m
lb
lb

Expert Solution

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

B (15.0 m) Ď (10.0 m) 30.0 53.0 25.0° Ċ (12.0 m) A (8.00 m) Consider the vectors shown above. What is the dot product ? O 55.0 m2 O -40.6 m2 O24.8 m2 O -55.0 m2 O 87.0 m2 O -24.8 m2
Question Four forces (measured in Newtons) act on a crate. The forces are given by the vectors: F₁ = 2121-136ĵ+ 241k N, F₂ = 108î+ 144) + 189k N. F3 = -400 + 180) + 240k N, and F₂ = -270k N Given: The magnitude of the resultant force = 449.2 N. The work done by the force F is 770.3J. The moment of the force F₂ = (-108î - 180k) N/m a) What is the angle (in degrees to 2 decimal places) between the force vectors F₂ and F3? b) What is the force vector, F, that acts in the opposite direction to the force F₂ and has magnitude of 203 Newtons?
A particle moves in the xy plane from the origin to a point having coordinates x=7 m and y=4 m under the influence of a force given by F= -2y^2i -2xj.
OA: 3 m/s B. 4 m/s OC. 5 m/s 60 N 50 kg A 50 kg cart is at rest when a 60 N force is applied, moving the cart 8 m until it hits an uncompressed spring. It then travels for another 2 m under the action of the force. The mass's velocity after moving 10 m is most nearly OD, 6 m/s 10 m 2 m llll k = 100 N/m
The figure shows a potted plant acted on by four forces. Evaluate the scalar product between forces 2 and 3 if 0 = 65°, = 132°, 4 F₁ = 20 N, F₂ = 16 N, 16 N, F3 = 12 N, and F₁ = 16 N. F3 F₂ F₁ f F3 9 FA Report your numerical answer below, assuming three significant figures. 42
What is the Net Work ? Wnet = Fnetd cos θ Cart Mass, mc . 284 kg Angle, theta 49 degrees Distance, d . 75 m Suspended Mass, ms . 300 kg Velocity 1 1. 343 m/s Velocity 2 1 . 354 m/s Velocity 3 1 . 348 m/s Average Velocity 1 . 348 m/s Kinetic Energy . 258 J
An advertisement shows a 1239 kg1239 kg car slowly pulling at constant speed a large passenger airplane to demonstrate the power of its newly designed 63.7 hp63.7 hp (horsepower) engine. During the pull, the car passes two landmarks spaced 25.0 m25.0 m apart in 14.3 s.14.3 s. The passenger plane being towed is a Boeing 707 with a total weight of 62.5 tons.62.5 tons. Calculate the force that opposes the motion. Assume that the efficiency of the car is such that 24.2%24.2% of the engine power is available to propel the car forward. How much work is performed by the car on the airplane during this time?How much work is performed by the airplane on the car during this time?
Determine the dot product of the following vectors A * B A=45 i + 65 j + 27 k B=46 i + 10 j + 43 k
Q9a. For the beam below, the point loads and distances are as follows: F1 = 11. 25 kN, F2 = 11.25 kN and F3 = 4.50 kN L1 = 2.25 m, L2 = 4.50 m, L3 = 4.50 m and L4 = 2.25 m Determine the reaction RA. Give your answer in kilonewtons (kN) to two decimal places. F1 F2 F3 B L2 L3 L4 L1 D. RB RA
Hello, need help with this problem. I got 706N but I'm not sure if that is the right answer. Here is my work: Weight of the crate = 120(9.8) = 1176 F = 0.6(1176) F = 705.6 N
I have tried this problem several times how do I do it correctly?
Common speech often uses the term "work" to refer to situations where, according to the physics definition of work, there is no actual work done. Find an example of this and explain why the non-physics public considers this work and what a proper physics response would be to this error. You must use ordinary language in an attempt to clarify what is happening do not rely on trigonometry or scalar dot products in you answer . Some examples you could consider include a person pushing on a wall and the wall not moving, a person doing a "bench seatisometric exercise where they squat against a wall, the moon being pulled by gravity as it orbits the earth, etc.

SEE MORE QUESTIONS