The likelihood of not rejecting the null hypothesis when the null hypothesis is false is ß, the probability of a type error. The likelihood of rejecting the null hypothesis when the null hypothesis is false is then 1-6. P191+ P292 Refer to the formula for ß as a function of proportions p₁ and P₂, where 2/2 is the critical value based on significance level a, (mp₁ + no ₂) = (ma₁ +na₂) m and in are the sample sizes of Brand A and Brand B samples, respectively, and a m (m + n) (m+n) B(D₂, P₂)-2/2√ √√5 ( ² + ²) - (0₂₁ - 0₂) - 0²/2√ √ ( = + ²) - (0₁-0₂) Given a 0.01, the critical value for this calculation is 2/2 Z20.005- Use the table standard normal curve areas to determine the critical value, rounded to two decimal places. ²a/2 = ²0.005 - Calculate using p₁ -0.50, P₂0.25, and m = n = 100. 5- (mp. + np₂) (m + n) 0.5(100)+([ 100 100 w 100 100 (100) Calculated using p₁ -0.50, P₂0.25, and mn 100, where d₁1-P₁ and 4₂1-P₂¹ (ma+na₂) (m+n) (10.5)(100)+(1-[ 0 + Calculate , rounding the result to five decimal places. P191+ P292 m 0.50(1-0.50) 0.25(1-[ 100 100 0 1)(100)

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The likelihood of not rejecting the null hypothesis when the null hypothesis is false is ß, the probability of a type II error. The likelihood of rejecting the null hypothesis when the null hypothesis is false is then 1 - ß.
(ma₁ + nq₂)
(m + n)
Refer to the formula for 8 as a function of proportions p₁ and P₂, where Z₁/2 is the critical value based on significance level a, p = (mp₁ + np₂), ā=.
z
(m + n)
862, 103) - + [²^ 2 √(- 3 (2+ + 2 ) – (0, - ²3)] -
√(³ 3 (²+ + ² ) - 10₁ - ³₂³)] _ •
B(P₁, P₂) = $
²a/2√
(P₁-P₂)
Calculate p using p₁ = 0.50, P₂ = 0.25, and m = n = 100.
(mp₁ + np₂)
(m + n)
0.5(100) +
p=
=
a
Given α = 0.01, the critical value for this calculation is Za/2=Z0.005. Use the table of standard normal curve areas to determine the critical value, rounded to two decimal places.
Za/2= ²0.005
0 =
100 + 100
P2
Calculated using p₁ -0.50, P₂ = 0.25, and m = n = 100, where a₁ = 1- P₁ and q₂ = 1 - P₂¹
9=
(ma₁ + ng₂)
(m + n)
(1 - 0.5)(100) + (1 -
+
100 + 100
Calculate σ, rounding the result to five decimal places.
P191
P292
m
n
(100)
0.50(1-0.50)
100
+
0.25(1-[
[ -5-²2√/
[-², 2√/³3 (+ + +) - 6 - 2³
(01
P2) ]
Ō
(100)
100
1
m and n are the sample sizes of Brand A and Brand B samples, respectively, and o =
P191
m
+
P292
n
Transcribed Image Text:The likelihood of not rejecting the null hypothesis when the null hypothesis is false is ß, the probability of a type II error. The likelihood of rejecting the null hypothesis when the null hypothesis is false is then 1 - ß. (ma₁ + nq₂) (m + n) Refer to the formula for 8 as a function of proportions p₁ and P₂, where Z₁/2 is the critical value based on significance level a, p = (mp₁ + np₂), ā=. z (m + n) 862, 103) - + [²^ 2 √(- 3 (2+ + 2 ) – (0, - ²3)] - √(³ 3 (²+ + ² ) - 10₁ - ³₂³)] _ • B(P₁, P₂) = $ ²a/2√ (P₁-P₂) Calculate p using p₁ = 0.50, P₂ = 0.25, and m = n = 100. (mp₁ + np₂) (m + n) 0.5(100) + p= = a Given α = 0.01, the critical value for this calculation is Za/2=Z0.005. Use the table of standard normal curve areas to determine the critical value, rounded to two decimal places. Za/2= ²0.005 0 = 100 + 100 P2 Calculated using p₁ -0.50, P₂ = 0.25, and m = n = 100, where a₁ = 1- P₁ and q₂ = 1 - P₂¹ 9= (ma₁ + ng₂) (m + n) (1 - 0.5)(100) + (1 - + 100 + 100 Calculate σ, rounding the result to five decimal places. P191 P292 m n (100) 0.50(1-0.50) 100 + 0.25(1-[ [ -5-²2√/ [-², 2√/³3 (+ + +) - 6 - 2³ (01 P2) ] Ō (100) 100 1 m and n are the sample sizes of Brand A and Brand B samples, respectively, and o = P191 m + P292 n
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