**Analysis of Fruit Fly Lifespan Using Two-Factor ANOVA**The study measured the life span (days) of three genotypes of fruit flies for both males and females. A two-factor ANOVA was performed to test for significant differences in life span among genotypes (factor A), between sexes (factor B), and to assess for a genotype-sex interaction. A 5% level of significance was used for each test.### Two-Factor ANOVA Table:| Source | SS | DF | MS | F ||--------------|--------|----|-----|-----|| Genotype | 454.01 | 3 | | || Sex | 73.30 | 2 | | || Interaction | 670.20 | 6 | | || Error | 1000.20| 36 | | || **Total** | 2197.71| 47 | | |**Definitions:**- **SS (Sum of Squares):** A measure of the total variability.- **DF (Degrees of Freedom):** The number of independent values or quantities which can be assigned to a statistical distribution.- **MS (Mean Square):** The average of the squared deviations (SS/DF).- **F:** The F-ratio, a statistic for comparing model fits.**Conclusion:**The question asks you to conclude whether there is a significant effect due to the three genotypes on the life span of fruit flies. You do not need to fill out the entire table to answer.**Conclusion Options:**1. There is no effect due to the three genotypes.2. There is a significant effect due to the three genotypes.3. The genotypes have a significant effect on the results of the Two-factor ANOVA.**Hint:**The conclusion should focus on the effect of the three genotypes on the life span of fruit flies specifically, considering the given information and the 5% significance level.

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The ANOVA table with some missing are given in the data.

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The life span (days) of three genotypes of fruit flies was measured for both males and females. Some calculations are presented below to test for significant differences in life span among genotypes (factor A), between sexes (factor B), and test for a genotype-sex interaction. Use a 5% level of significance for each test. Two-Factor ANOVA Source SS DF MS F Genotype 454.01 3 Sex 73.30 Interaction 670.20 6. Error 1000.20 36 Total 2197.71 47 What is your conclusion regarding the effects of three genotypes on the life span of fruit flies? Hint* this question is asking you to choose a conclusion for a single factor only. You do not have to fill out the entire table. There is no effect due to the three genotypes. There is a significant effect due to the three genotypes. The genotypes have a significant effect on the results of the Two-factor ANOVA.

The life span (days) of three genotypes of fruit flies was measured for both males and females. Some calculations are presented below to test for significant differences in life span among genotypes (factor A), between sexes (factor B), and test for a genotype-sex interaction. Use a 5% level of significance for each test. Two-Factor ANOVA Source SS DF MS F Genotype 454.01 3 Sex 73.30 Interaction 670.20 6. Error 1000.20 36 Total 2197.71 47 What is your conclusion regarding the effects of three genotypes on the life span of fruit flies? Hint* this question is asking you to choose a conclusion for a single factor only. You do not have to fill out the entire table. There is no effect due to the three genotypes. There is a significant effect due to the three genotypes. The genotypes have a significant effect on the results of the Two-factor ANOVA.

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Types of Bias

Statistics is the study of data collection, organization, analysis, interpretation, and presentation. Statistical bias is a characteristic of a statistical technique or its findings in which the expected value deviates from the actual root quantitative parameter being estimated. According to the actual definition of bias, it refers to the tendency of a statistic to overestimate or underestimate a parameter.

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Question

**Analysis of Fruit Fly Lifespan Using Two-Factor ANOVA**

The study measured the life span (days) of three genotypes of fruit flies for both males and females. A two-factor ANOVA was performed to test for significant differences in life span among genotypes (factor A), between sexes (factor B), and to assess for a genotype-sex interaction. A 5% level of significance was used for each test.

### Two-Factor ANOVA Table:

| Source | SS | DF | MS | F |
|--------------|--------|----|-----|-----|
| Genotype | 454.01 | 3 | | |
| Sex | 73.30 | 2 | | |
| Interaction | 670.20 | 6 | | |
| Error | 1000.20| 36 | | |
| **Total** | 2197.71| 47 | | |

**Definitions:**
- **SS (Sum of Squares):** A measure of the total variability.
- **DF (Degrees of Freedom):** The number of independent values or quantities which can be assigned to a statistical distribution.
- **MS (Mean Square):** The average of the squared deviations (SS/DF).
- **F:** The F-ratio, a statistic for comparing model fits.

**Conclusion:**
The question asks you to conclude whether there is a significant effect due to the three genotypes on the life span of fruit flies. You do not need to fill out the entire table to answer.

**Conclusion Options:**
1. There is no effect due to the three genotypes.
2. There is a significant effect due to the three genotypes.
3. The genotypes have a significant effect on the results of the Two-factor ANOVA.

**Hint:**
The conclusion should focus on the effect of the three genotypes on the life span of fruit flies specifically, considering the given information and the 5% significance level.

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