The life expectancy of Timely brand watches is normally distributed with a mean of four years and a standard deviation of eight months. a. What is the probability that a randomly selected watch will be in working condition for more than five years? (Round to four decimal places.) b. The company has a three-year warranty period on their watches. What percentage of their watches will be in operating condition after the warranty period? (Round to four decimal places.) c. What is the minimum and the maximum life expectancy of the middle 80% of the watches? (Round to two decimal places.) Type the Probability Expression: Find the Solution: x1 =
The life expectancy of Timely brand watches is normally distributed with a mean of four years and a standard deviation of eight months. a. What is the probability that a randomly selected watch will be in working condition for more than five years? (Round to four decimal places.) b. The company has a three-year warranty period on their watches. What percentage of their watches will be in operating condition after the warranty period? (Round to four decimal places.) c. What is the minimum and the maximum life expectancy of the middle 80% of the watches? (Round to two decimal places.) Type the Probability Expression: Find the Solution: x1 =
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Problem 1P
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![The life expectancy of Timely brand watches is normally distributed with a mean of four years and a standard deviation of eight months.
μ=
0 =
a. What is the probability that a randomly selected watch will be in working condition for more than five years?
(Round to four decimal places.)
b. The company has a three-year warranty period on their watches. What percentage of their watches will be in
operating condition after the warranty period? (Round to four decimal places.)
c. What is the minimum and the maximum life expectancy of the middle 80% of the watches? (Round to two
decimal places.)
d. Ninety-five percent of the watches will have a life expectancy of at least how many months? (Round to two
decimal places.)
Type the Probability
Expression:
Find the Solution:
x1 =
x2 =
x1 =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8095922b-c6e9-41a5-aaf9-40795a5664d9%2F37cdfb91-881e-4920-a2f2-256876cbba1a%2Fcsj2dx_processed.png&w=3840&q=75)
Transcribed Image Text:The life expectancy of Timely brand watches is normally distributed with a mean of four years and a standard deviation of eight months.
μ=
0 =
a. What is the probability that a randomly selected watch will be in working condition for more than five years?
(Round to four decimal places.)
b. The company has a three-year warranty period on their watches. What percentage of their watches will be in
operating condition after the warranty period? (Round to four decimal places.)
c. What is the minimum and the maximum life expectancy of the middle 80% of the watches? (Round to two
decimal places.)
d. Ninety-five percent of the watches will have a life expectancy of at least how many months? (Round to two
decimal places.)
Type the Probability
Expression:
Find the Solution:
x1 =
x2 =
x1 =
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Step 1: Define the given variables.
VIEWStep 2: Determine the value of mean and the standard deviation.
VIEWStep 3: Obtain the probability that a randomly selected watch will be in working condition for more than 5 y
VIEWStep 4: Obtain the percentage of their watches will be in operating condition after the warranty period.
VIEWStep 5: Obtain the minimum and the maximum life expectancy of the middle 80% of the watches.
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