the level order traversal of the Binary Tree's nodes' values - from left to right, level by level. /* Class to represent Tree node +/ class Node { int data; Node left, right; public Node(int item) data = item; left = null; right = null; Below is an illustrated sample of Binary Tree nodes for your reference, which in-fact is the same example we discussed in the lecture.
the level order traversal of the Binary Tree's nodes' values - from left to right, level by level. /* Class to represent Tree node +/ class Node { int data; Node left, right; public Node(int item) data = item; left = null; right = null; Below is an illustrated sample of Binary Tree nodes for your reference, which in-fact is the same example we discussed in the lecture.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
java
Please explain the TEST-CASE in short sentence for the code in the attachment.

Transcribed Image Text:The root element of the binary tree is given to you. Your task is to return
1
the level order traversal of the Binary Tree's nodes' values – from left to right,
level by level.
/* Class to represent Tree node */
class Node {
int data;
Node left, right;
public Node(int item)
data = item;
left = null;
right = null;
Below is an illustrated sample of Binary Tree nodes for your reference, which
in-fact is the same example we discussed in the lecture.
tree.root ▪ new Node (4);
tree.root.left = new Node (2);
tree.root.right = new Node (6);
tree.root.left.left = new Node(1);
tree.root.left.right = new Node (3);
tree.root.right.left = new Node (5);
tree.root.right.right = new Node (7);
Your code will need to return all the nodes of the Binary Tree in Level Order
Traversal fashion - from left to right. That is: 4 2 6 1 3 5 7
Level Order Tree Traversal with the help of the Queue data-structure should
meet the following complexities as stated below.
Time Complexity: 0(n)
Space Complexity: O(n)
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