The lens-makers' equation can be written as 1 7- (2²2-1) (21-24) = f R₁ R₂ where n₂ represents the index of refraction of the lens material and n₁ is that of the medium surrounding the lens. (a) A certain lens has focal length 53.6 cm in the air and index of refraction 1.55. Find its focal length in water. (Give your answer in cm.) cm (b) A certain mirror has focal length 53.6 cm in the air. Find its focal length in water. (Give your answer in cm.) cm

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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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The lens-makers' equation can be written as

\[
\frac{1}{f} = \left( \frac{n_2}{n_1} - 1 \right) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)
\]

where \( n_2 \) represents the index of refraction of the lens material and \( n_1 \) is that of the medium surrounding the lens.

**(a)** A certain lens has a focal length of 53.6 cm in the air and an index of refraction of 1.55. Find its focal length in water. (Give your answer in cm.)

[Blank for answer] cm

**(b)** A certain mirror has a focal length of 53.6 cm in the air. Find its focal length in water. (Give your answer in cm.)

[Blank for answer] cm
Transcribed Image Text:The lens-makers' equation can be written as \[ \frac{1}{f} = \left( \frac{n_2}{n_1} - 1 \right) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \] where \( n_2 \) represents the index of refraction of the lens material and \( n_1 \) is that of the medium surrounding the lens. **(a)** A certain lens has a focal length of 53.6 cm in the air and an index of refraction of 1.55. Find its focal length in water. (Give your answer in cm.) [Blank for answer] cm **(b)** A certain mirror has a focal length of 53.6 cm in the air. Find its focal length in water. (Give your answer in cm.) [Blank for answer] cm
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