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The lengths of the edges of a triangular canvas are 110 feet, 140 feet, and 180 feet. You want to waterproof the tarp. If one can of waterproofing will treat 1,000 square feet, how many cans do you need? (Round your answer up to the nearest whole number.) cans

The lengths of the edges of a triangular canvas are 110 feet, 140 feet, and 180 feet. You want to waterproof the tarp. If one can of waterproofing will treat 1,000 square feet, how many cans do you need? (Round your answer up to the nearest whole number.) cans

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter10: Measurement, Area, And Volume
Section: Chapter Questions
Problem 13PTTS
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The lengths of the edges of a triangular canvas are 110 feet, 140 feet, and 180 feet. You want to waterproof the tarp. If one can of waterproofing will treat 1,000 square feet, how many cans do you need? (Round your answer up to the nearest whole number.) cans
Transcribed Image Text:The lengths of the edges of a triangular canvas are 110 feet, 140 feet, and 180 feet. You want to waterproof the tarp. If one can of waterproofing will treat 1,000 square feet, how many cans do you need? (Round your answer up to the nearest whole number.) cans
Expert Solution
Step 1

Given:

  • Edges of the triangular canvas are 110 feet , 140 feet and 180 feet.

Determine the semi perimeter using the formula s=12a+b+c.

Substitute the respective values.

s=12110 feet+140 feet+180 feets=12320 feets=215 feet

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