The lengths of a professor's classes has a continuous uniform distribution between 49.29 min and 55.55 min. If one such class is randomly selected, find P53 P53 = (Report answer accurate to 4 decimal places.)

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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**Problem Description:**

The lengths of a professor’s classes have a continuous uniform distribution between 49.29 minutes and 55.55 minutes. If one such class is randomly selected, find \( P_{53} \).

**Solution:**

To find \( P_{53} \), which represents the 53rd percentile of the distribution, you would use the formula for the percentile of a uniform distribution:

\[ P_k = a + \frac{k}{100} \times (b - a) \]

where:
- \( a \) is the lower limit of the distribution (49.29 minutes),
- \( b \) is the upper limit of the distribution (55.55 minutes),
- \( k \) is the percentile you wish to find (53).

**Calculation:**

\[ P_{53} = 49.29 + \frac{53}{100} \times (55.55 - 49.29) \]

**Report Answer:**

Make sure to report the answer accurate to 4 decimal places.
Transcribed Image Text:**Problem Description:** The lengths of a professor’s classes have a continuous uniform distribution between 49.29 minutes and 55.55 minutes. If one such class is randomly selected, find \( P_{53} \). **Solution:** To find \( P_{53} \), which represents the 53rd percentile of the distribution, you would use the formula for the percentile of a uniform distribution: \[ P_k = a + \frac{k}{100} \times (b - a) \] where: - \( a \) is the lower limit of the distribution (49.29 minutes), - \( b \) is the upper limit of the distribution (55.55 minutes), - \( k \) is the percentile you wish to find (53). **Calculation:** \[ P_{53} = 49.29 + \frac{53}{100} \times (55.55 - 49.29) \] **Report Answer:** Make sure to report the answer accurate to 4 decimal places.
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