The length of time required to complete the test normally distributed with mean 75 minutes and standard deviation 15 minutes. achievement Sufficient time for 95% of students to complete the

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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Please show all steps. Please DO NOT skip any steps as I will not understand what you actually did. QUESTION: How did you get Z = 1.65 from 95%z. Would that not be Z = 1.960? Please show every step. This has confused me.
The length of time required to complete the
achievement test normally distributed with mean
75 minutes and standard deviation 15 minutes.
Sufficient time for 95% of students to complete the
test.
P(z)= 0.95
Where, the z value corresponds to the 0.95 is 1.65
Now,
P(z)=0.95
z=1.65
-=1.65
x-75
15
Area = 0.95
u = 75
z = 1.65
x = 99.75
X= =(1.65 × 15)+75
=99.75
Thus, 99.75 minutes required by 95% of students
to complete the test.
Transcribed Image Text:The length of time required to complete the achievement test normally distributed with mean 75 minutes and standard deviation 15 minutes. Sufficient time for 95% of students to complete the test. P(z)= 0.95 Where, the z value corresponds to the 0.95 is 1.65 Now, P(z)=0.95 z=1.65 -=1.65 x-75 15 Area = 0.95 u = 75 z = 1.65 x = 99.75 X= =(1.65 × 15)+75 =99.75 Thus, 99.75 minutes required by 95% of students to complete the test.
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