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The length of a rectangle is 5 more than thrice the width. If the perimeter is 106, what is its area? Answer: x = and y = Solution: let x width of the rectangle R: y = length of the rectangle Length E: = 3x + 5 width = x S P = 2L + 2W A: x = and y = Area of the rectangle = length x width A = square units C: P = 2L + 2W Answer GEOMETRIC PROBLEM The length of a rectangle is 5 more than thrice the width. If Answer: x = Answer: y = the perimeter is 106, what is its area? Answer: A = [c square units [a] [b]

The length of a rectangle is 5 more than thrice the width. If the perimeter is 106, what is its area? Answer: x = and y = Solution: let x width of the rectangle R: y = length of the rectangle Length E: = 3x + 5 width = x S P = 2L + 2W A: x = and y = Area of the rectangle = length x width A = square units C: P = 2L + 2W Answer GEOMETRIC PROBLEM The length of a rectangle is 5 more than thrice the width. If Answer: x = Answer: y = the perimeter is 106, what is its area? Answer: A = [c square units [a] [b]

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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The length of a rectangle is 5 more than thrice the width. If the perimeter is 106, what is its area? Answer: x = and y = Solution: let x = width of the rectangle R: y = length of the rectangle Length E: = 3x + 5 width = x S P = 2L + 2W A: X = _ and y = Area of the rectangle = length x width A = square units C: P = 2L + 2W Answer:GEOMETRIC PROBLEM The length of a rectangle is 5 more than thrice the width. If Answer: x = Answer: y = the perimeter is 106, what is its area? Answer: A = [C square units [a] [b]
Transcribed Image Text:The length of a rectangle is 5 more than thrice the width. If the perimeter is 106, what is its area? Answer: x = and y = Solution: let x = width of the rectangle R: y = length of the rectangle Length E: = 3x + 5 width = x S P = 2L + 2W A: X = _ and y = Area of the rectangle = length x width A = square units C: P = 2L + 2W Answer:GEOMETRIC PROBLEM The length of a rectangle is 5 more than thrice the width. If Answer: x = Answer: y = the perimeter is 106, what is its area? Answer: A = [C square units [a] [b]
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