The length of a rectangle is 5 more than thrice the width. If the perimeter is 106, what is its area? Answer: x = and y = Solution: let x width of the rectangle R: y = length of the rectangle Length E: = 3x + 5 width = x S P = 2L + 2W A: x = and y = Area of the rectangle = length x width A = square units C: P = 2L + 2W Answer GEOMETRIC PROBLEM The length of a rectangle is 5 more than thrice the width. If Answer: x = Answer: y = the perimeter is 106, what is its area? Answer: A = [c square units [a] [b]
The length of a rectangle is 5 more than thrice the width. If the perimeter is 106, what is its area? Answer: x = and y = Solution: let x width of the rectangle R: y = length of the rectangle Length E: = 3x + 5 width = x S P = 2L + 2W A: x = and y = Area of the rectangle = length x width A = square units C: P = 2L + 2W Answer GEOMETRIC PROBLEM The length of a rectangle is 5 more than thrice the width. If Answer: x = Answer: y = the perimeter is 106, what is its area? Answer: A = [c square units [a] [b]
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter4: Polynomials
Section4.9: Area Problems
Problem 1P
Related questions
Question
![The length of a rectangle is 5 more than thrice the width. If the perimeter is 106, what is its area?
Answer: x =
and y =
Solution:
let x = width of the rectangle
R:
y = length of the rectangle
Length
E:
= 3x + 5
width = x
S P = 2L + 2W
A: X = _
and y =
Area of the rectangle = length x width
A =
square units
C: P = 2L + 2W
Answer:GEOMETRIC PROBLEM
The length of a rectangle is 5 more than thrice the width. If Answer: x = Answer: y =
the perimeter is 106, what is its area?
Answer: A = [C
square units
[a]
[b]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5e97668d-3578-4ee5-9be9-64d089a88a73%2F6be7374f-b010-4278-a303-91c719455191%2Fod06s6h_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The length of a rectangle is 5 more than thrice the width. If the perimeter is 106, what is its area?
Answer: x =
and y =
Solution:
let x = width of the rectangle
R:
y = length of the rectangle
Length
E:
= 3x + 5
width = x
S P = 2L + 2W
A: X = _
and y =
Area of the rectangle = length x width
A =
square units
C: P = 2L + 2W
Answer:GEOMETRIC PROBLEM
The length of a rectangle is 5 more than thrice the width. If Answer: x = Answer: y =
the perimeter is 106, what is its area?
Answer: A = [C
square units
[a]
[b]
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