The length of a new rectangular playing field is 8 yards longer than double the width. If the perimeter of the rectangular playing field is 340 yards, what are its dimensions? The width is yards. The length is yards. ...

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.5: Multiplication With The Addition-or-subtraction Method
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**Problem Statement:**

The length of a new rectangular playing field is 8 yards longer than double the width. If the perimeter of the rectangular playing field is 340 yards, what are its dimensions?

---

To find the dimensions of the rectangular playing field, we need to solve for two variables: the width and the length. 

**Given Information:**

1. The perimeter of the rectangular playing field is 340 yards.
2. The length (L) of the field is 8 yards longer than double the width (W).

**Equations:**

1. Perimeter of a rectangle: \( P = 2L + 2W \)
2. Given problem: \( L = 2W + 8 \)

**Steps to Solve:**

1. Substitute the length formula from equation 2 into equation 1.
2. Solve for the width (W).
3. Use the width to find the length (L).

You can calculate it as follows:

The width is [  ___ ] yards.

The length is [  ___ ] yards.
Transcribed Image Text:**Problem Statement:** The length of a new rectangular playing field is 8 yards longer than double the width. If the perimeter of the rectangular playing field is 340 yards, what are its dimensions? --- To find the dimensions of the rectangular playing field, we need to solve for two variables: the width and the length. **Given Information:** 1. The perimeter of the rectangular playing field is 340 yards. 2. The length (L) of the field is 8 yards longer than double the width (W). **Equations:** 1. Perimeter of a rectangle: \( P = 2L + 2W \) 2. Given problem: \( L = 2W + 8 \) **Steps to Solve:** 1. Substitute the length formula from equation 2 into equation 1. 2. Solve for the width (W). 3. Use the width to find the length (L). You can calculate it as follows: The width is [ ___ ] yards. The length is [ ___ ] yards.
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