The leg and cast in the figure below weigh 374 N (w,). Determine the weight w, and the angle a needed so that no force is exerted on the hip joint by the leg plus cast. W2 = a %3D w2 110 N 40 α wi Need Help? Read It
The leg and cast in the figure below weigh 374 N (w,). Determine the weight w, and the angle a needed so that no force is exerted on the hip joint by the leg plus cast. W2 = a %3D w2 110 N 40 α wi Need Help? Read It
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Educational Website Content: Physics - Mechanics
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#### Problem Statement
The leg and cast in the figure below weigh \( 374 \, \text{N} \) (\( w_1 \)). Determine the weight \( w_2 \) and the angle \( \alpha \) needed so that no force is exerted on the hip joint by the leg plus cast.
- Weight of leg and cast (\( w_1 \)) = \( 374 \, \text{N} \)
- Weight \( w_2 \) = \( \)
- Angle \( \alpha \) = \( \)
#### Diagram Description
The diagram depicts a patient lying on their back with a cast on their elevated leg. A pulley system is used to apply tension to the leg:
1. There is a weight labeled \( 110 \, \text{N} \) attached to a string that passes through a pulley.
2. The string is connected to a second weight labeled \( w_2 \) which is attached to another pulley above the bed.
3. The leg is elevated at an angle \( \alpha \), maintained by the tension in the string.
4. The force of gravity acts downward on the leg and cast combination with a weight of \( 374 \, \text{N} \) (\( w_1 \)).
The objective is to balance the forces in such a way that the hip joint does not experience any resultant force from the leg and cast.
#### Variables:
- \( w_1 \) = Weight of the leg and cast
- \( w_2 \) = Weight needed for balance
- \( \alpha \) = Angle needed for balance
#### Guidelines for Calculation:
1. **Force Balance in Vertical Direction**:
- The tension from \( w_2 \) and the 110 N weight must balance the vertical component of \( w_1 \).
2. **Force Balance in Horizontal Direction**:
- The forces must balance each other so that the horizontal components cancel out.
3. **Calculation of Angles**:
- Use trigonometric relationships to resolve forces into components and find \( \alpha \).
---
For further assistance, consult your instructor or click the [Read It] button for additional hints.
Need Help?
- [Read It]
---
*This educational content is provided to help understand the principles of force balancing in static equilibrium scenarios.*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b26ac75-c955-42a6-8738-a8e397e8b37e%2Fba944388-75e2-4667-87bc-c3373428b1f2%2F2z8g8mp.jpeg&w=3840&q=75)
Transcribed Image Text:### Educational Website Content: Physics - Mechanics
---
#### Problem Statement
The leg and cast in the figure below weigh \( 374 \, \text{N} \) (\( w_1 \)). Determine the weight \( w_2 \) and the angle \( \alpha \) needed so that no force is exerted on the hip joint by the leg plus cast.
- Weight of leg and cast (\( w_1 \)) = \( 374 \, \text{N} \)
- Weight \( w_2 \) = \( \)
- Angle \( \alpha \) = \( \)
#### Diagram Description
The diagram depicts a patient lying on their back with a cast on their elevated leg. A pulley system is used to apply tension to the leg:
1. There is a weight labeled \( 110 \, \text{N} \) attached to a string that passes through a pulley.
2. The string is connected to a second weight labeled \( w_2 \) which is attached to another pulley above the bed.
3. The leg is elevated at an angle \( \alpha \), maintained by the tension in the string.
4. The force of gravity acts downward on the leg and cast combination with a weight of \( 374 \, \text{N} \) (\( w_1 \)).
The objective is to balance the forces in such a way that the hip joint does not experience any resultant force from the leg and cast.
#### Variables:
- \( w_1 \) = Weight of the leg and cast
- \( w_2 \) = Weight needed for balance
- \( \alpha \) = Angle needed for balance
#### Guidelines for Calculation:
1. **Force Balance in Vertical Direction**:
- The tension from \( w_2 \) and the 110 N weight must balance the vertical component of \( w_1 \).
2. **Force Balance in Horizontal Direction**:
- The forces must balance each other so that the horizontal components cancel out.
3. **Calculation of Angles**:
- Use trigonometric relationships to resolve forces into components and find \( \alpha \).
---
For further assistance, consult your instructor or click the [Read It] button for additional hints.
Need Help?
- [Read It]
---
*This educational content is provided to help understand the principles of force balancing in static equilibrium scenarios.*
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