The left graph is y = g(x). The right graph is y = h(v). True of False. Explain your reasoning. True False h(v) dv True False True False h(v) dv < 0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Graphs:**

- The left graph represents the function \( y = g(x) \).
  - It starts at the point \((0, 0)\), dips below the x-axis, peaks around \((2, 3)\), crosses the x-axis at \((3, 0)\), and then goes below the x-axis.
- The right graph represents the function \( y = h(v) \).
  - It begins at \((0, -4)\), rises to a peak near \((2, 4)\), and then descends sharply to the x-axis at \((4, 0)\).

**Questions:**

1. True or False: Explain your reasoning.
   - \( \int_0^4 g(x) \, dx < \int_0^4 h(v) \, dv \)
     - [ ] True 
     - [ ] False 

2. True or False: Explain your reasoning.
   - \( \int_6^2 g(x) \, dx < 0 \)
     - [ ] True 
     - [ ] False 

3. True or False: Explain your reasoning.
   - \( \int_0^4 h(v) \, dv < 0 \)
     - [ ] True 
     - [ ] False
Transcribed Image Text:**Graphs:** - The left graph represents the function \( y = g(x) \). - It starts at the point \((0, 0)\), dips below the x-axis, peaks around \((2, 3)\), crosses the x-axis at \((3, 0)\), and then goes below the x-axis. - The right graph represents the function \( y = h(v) \). - It begins at \((0, -4)\), rises to a peak near \((2, 4)\), and then descends sharply to the x-axis at \((4, 0)\). **Questions:** 1. True or False: Explain your reasoning. - \( \int_0^4 g(x) \, dx < \int_0^4 h(v) \, dv \) - [ ] True - [ ] False 2. True or False: Explain your reasoning. - \( \int_6^2 g(x) \, dx < 0 \) - [ ] True - [ ] False 3. True or False: Explain your reasoning. - \( \int_0^4 h(v) \, dv < 0 \) - [ ] True - [ ] False
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