The least-square regression line for the given data is y = 0.449x - 30.27. Determine the residual of a data point for w x = 98 and y = 15, rounding to three decimal places. Temperature, x Number of absences, y A. 28.732 OB. 1.268 C. 121.535 D. 13.732 72 3 85 7 91 10 90 88 98 75 100 10 8 15 4 15 80 5

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The least-square regression line for the given data is \( \hat{y} = 0.449x - 30.27 \). Determine the residual of a data point for which \( x = 98 \) and \( y = 15 \), rounding to three decimal places.

| Temperature, \( x \) | 72 | 85 | 91 | 90 | 88 | 98 | 75 | 100 | 80 |
|------------------------|----|----|----|----|----|----|----|-----|----|
| Number of absences, \( y \) | 3  | 7  | 10 | 10 | 8  | 15 | 4  | 15  | 5  |

Options:
- A. 28.732
- **B. 1.268**
- C. 121.535
- D. 13.732

To find the residual, use the equation to calculate the predicted value of \( y \) when \( x = 98 \), and subtract this from the actual \( y \)-value (15). The residual is the difference between the observed value and the predicted value.
Transcribed Image Text:The least-square regression line for the given data is \( \hat{y} = 0.449x - 30.27 \). Determine the residual of a data point for which \( x = 98 \) and \( y = 15 \), rounding to three decimal places. | Temperature, \( x \) | 72 | 85 | 91 | 90 | 88 | 98 | 75 | 100 | 80 | |------------------------|----|----|----|----|----|----|----|-----|----| | Number of absences, \( y \) | 3 | 7 | 10 | 10 | 8 | 15 | 4 | 15 | 5 | Options: - A. 28.732 - **B. 1.268** - C. 121.535 - D. 13.732 To find the residual, use the equation to calculate the predicted value of \( y \) when \( x = 98 \), and subtract this from the actual \( y \)-value (15). The residual is the difference between the observed value and the predicted value.
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