the lead in an aqueous lead (II) nitrate solution can be precipitated out by adding potassium iodide. if we have 807.0 mL of 0.607 M lead (II) nitrate solution, how much 2.93 M potassium iodide must we add to exactly all the lead (II) ions? round to correct number of sig figs 2 Kl(aq) + Pb(NO3)2(aq) --> Pbl2(s) + 2 KNO3(aq)

Q: In the reaction between KCl(aq) and AgNO3(aq), a precipitate of AgCl(s) will form. What mass (in…

A: Molarity of AgNO3 solution = 0.220 Volume of AgNO3 solution = 27.2*10-3 Molar mass of KCl= 74.55…

Q: You have 500 mL of a 0.125 M HCl(aq) solution and you want to dilute it to exactly 0.100 M. How much…

A: The given problem relates to stock dilution, so we can use the below relation to calculate the…

Q: You have 15 mL of a 0.25 M NaCl(aq) solution. What volume should you dilute it to in order to obtain…

A: Given: The initial volume (V1) of NaCl (sodium chloride) solution is 15 mL The initial molarity (M1)…

Q: A 2.88 g sample of iron ore is transformed to a solution of iron(II) sulfate, FeSO4. This solution…

A:

Q: How many milliliters of 11.0 M HCl(aq) are needed to prepare 310.0mL of 1.00 M HCl(aq)?

A: The required volume is determined by using following formula, M1V1=M2V2

Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Na3PO4 reacts with 44.5 mL of…

A:

Q: How much solvent must be added to 25.0 mL of a 10.0 M HBr(aq) solution to form a 4.00 M HBr(aq)…

A: Let V Volumn is added

Q: Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to…

A: Given, Molarity of barium hydroxide solution = 0.281 M = 0.281 mol/L Volume of barium hydroxide…

Q: How many grams of Pb(IO3)2(s) are precipitated when 27.0 mL of 3.00 M Pb(NO3)2(aq) are mixed with…

A: The balanced chemical equation is given below.

Q: A 70 mL sample of brine, a wastewater byproduct of an industrial process containing high…

A: Given Concentration of AgNO3 = 1M Volume of AgNO3 = 111 mL Volume of brine = 70 mL

Q: How many grams of Cu(OH)2 will precipitate when excess KOH solution is added to 41.0 mL of 0.618 M…

A: To solve this problem we will use the given balanced chemical equation.

Q: How many grams of Ag₂CO3 will precipitate when excess Na2CO3 solution is added to 49.0 mL of 0.590 M…

A:

Q: A student requires 45.0 grams of solid silver chloride to precipitate.  What volume of a 0.50 M…

A: As here NaCl is used in excess amount the limiting reagent is AgNO3 from here we can calculate the…

Q: How many grams of Cu(OH)2 will precipitate when excess NaOH solution is added to 60.0 mL of 0.684 M…

A: The balanced equation is CuBr2(aq)  +  2 NaOH(aq)  →  Cu(OH)2(s)  +  2 NaBr(aq)Volume of solution =…

Q: 252 mL of 3.00 M H2SO4(aq) are added to 1.50 L of 0.500 M H2SO4(aq). What is the concentration of…

A: Concentration in terms molarity of is defined as the number of moles of solute present in per litre…

Q: By titration, it is found that 66.3 mL of 0.116 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Given Molarity Of NaOH = 0.116 M volume of NaOH = 66.3 ml volume of HCl = 25.0 ml

Q: 4. If 16.0 mL of water are added to 31.5 mL of 0.586 M Ba(OH)₂ (aq), what is the new solution…

A: To find the new molarity of the given solution after adding water.

Q: By titration, it is found that 96.5 mL of 0.154 M NaOH(aq) is needed to neutralize 25.0 mL of…

A: Given information:Volume of NaOH (V1)= 96.5 mLVolume of HCl (V2)= 25.0 mLMolarity of NaOH (M1)=…

Q: How many milliliters of 11.0 M HCl(aq) are needed to prepare 220.0 mL of 1.00 M HCl(aq)?

A: Please find your solution below : Molarity is defined as the number of moles of solute in one litre…

Q: f 23.1 g of NaOH (MM = 40.00 g/mol) are added to a 500.0 mL volumetric flask, and water is added to…

A: Given data mass of NaOH = 23.1 g Molar mass of NaOH = 40.00 g Volume of the solution =  500.0 mL The…

Q: Excess Na2SO4(aq) is added to a 4.41×102 mL sample of industrial waste containing Ba2+ ions. If 55.5…

A:

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".