The lattice constant of a face-centered-cubic structure is 4.75 Å. Determine the vol- ume density of atoms. ( ɔ 01 The volume density of atoms for a simple cubic lattice is 3 x 1022 cm-. Assume that the atoms are hard spheres with each atom touching its nearest neighbor. Determine the lattice constant and the radium of the atom. (y 1 = E = °p°su

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HW(2 questions)
The lattice constant of a face-centered-cubic structure is 4.75 Å. Determine the vol-
ume density of atoms. (_uɔ 01 X
The volume density of atoms for a simple cubic lattice is 3 x 1022 cm-. Assume that
the atoms are hard spheres with each atom touching its nearest neighbor. Determine
the lattice constant and the radium of the atom. (y 1 Ɛ = 0p°su
Transcribed Image Text:HW(2 questions) The lattice constant of a face-centered-cubic structure is 4.75 Å. Determine the vol- ume density of atoms. (_uɔ 01 X The volume density of atoms for a simple cubic lattice is 3 x 1022 cm-. Assume that the atoms are hard spheres with each atom touching its nearest neighbor. Determine the lattice constant and the radium of the atom. (y 1 Ɛ = 0p°su
HW(2 questions)
Determine the distance between nearest (110) planes in a simple cubic lattice with a
lattice constant of an = 4.83 Å. (y
The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface
density of atoms for (a)a (100) plane and (b) a (110) plane.
(Ans. (a) 8.86 x 104 cm-, (b) 6.27 x 104 cm-2]
Transcribed Image Text:HW(2 questions) Determine the distance between nearest (110) planes in a simple cubic lattice with a lattice constant of an = 4.83 Å. (y The lattice constant of a face-centered-cubicstructure is 4.75 Å. Calculate the surface density of atoms for (a)a (100) plane and (b) a (110) plane. (Ans. (a) 8.86 x 104 cm-, (b) 6.27 x 104 cm-2]
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