The lateral surface of a water bottle consists of a circular cylinder of radius 3 and height 6, topped off by a truncated hyperboloid of one sheet of height 4. Assume the top of the truncated hyperboloid has a 10 radius of 7. Find two equations that, when graphed together, form the lateral surface of the bottle. Determine the correct equations. Select all that apply. OB. x? - y? = 9 O A. x y? 9*9 - 5(z – 10)2 = 1 O C. 9x? + 9y? - 5(z – 10)2 = 1 O E. 9x? + 9y? = 1 O G. x? + y² - z² = 9 O. x? + y? + z? = 9 OD. 2+ y? = 9 OF. - 9x2 - 9y? ++ 5(z – 10)? = 1 O H. x2 + y2 - (z - 10)² = 1 O J. 9x? + 9y? + 5(z – 10)² = 1
The lateral surface of a water bottle consists of a circular cylinder of radius 3 and height 6, topped off by a truncated hyperboloid of one sheet of height 4. Assume the top of the truncated hyperboloid has a 10 radius of 7. Find two equations that, when graphed together, form the lateral surface of the bottle. Determine the correct equations. Select all that apply. OB. x? - y? = 9 O A. x y? 9*9 - 5(z – 10)2 = 1 O C. 9x? + 9y? - 5(z – 10)2 = 1 O E. 9x? + 9y? = 1 O G. x? + y² - z² = 9 O. x? + y? + z? = 9 OD. 2+ y? = 9 OF. - 9x2 - 9y? ++ 5(z – 10)? = 1 O H. x2 + y2 - (z - 10)² = 1 O J. 9x? + 9y? + 5(z – 10)² = 1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Transcribed Image Text:The lateral surface of a water bottle consists of a circular cylinder of radius 3 and height 6, topped off by a truncated hyperboloid of one sheet of height 4. Assume the top of the truncated hyperboloid has a
O 10
1
radius of 5. Find two equations that, when graphed together, form the lateral surface of the bottle.
6.
Determine the correct equations. Select all that apply.
O A. x2
y2
- 5(z - 10)2 = 1
O B. x2 - y? = 9
O C. 9x2 + 9y? - 5(z – 10)2 = 1
O D. x² + y² = 9
O E. 9x2 + 9y2 = 1
O F. - 9x2 – 9y² + 5(z – 10)2 = 1
O G. x2 + y? - z² = 9
O1. x? + y? + z? =9
O H. x² + y² - (z – 10)2 = 1
O J. 9x2 + 9y² + 5(z – 10)2 = 1
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