The Laplace transform of the signal x (t) is X(s) = 10(8²+3) s(s²+25+5)* The initial value of the signal x(0¯) =

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The Laplace transform of the signal \( x(t) \) is given by:

\[
X(s) = \frac{10(s^2 + 3)}{s(s^2 + 2s + 5)}
\]

The initial value of the signal \( x(0^-) \) is _____.
Transcribed Image Text:The Laplace transform of the signal \( x(t) \) is given by: \[ X(s) = \frac{10(s^2 + 3)}{s(s^2 + 2s + 5)} \] The initial value of the signal \( x(0^-) \) is _____.
The Laplace transform of the signal \( x(t) \) is 

\[
X(s) = \frac{10(s^2 + 3)}{s(s^2 + 2s + 5)}.
\]

The final value of the signal \( x(+\infty) = \underline{\hspace{1cm}} \)
Transcribed Image Text:The Laplace transform of the signal \( x(t) \) is \[ X(s) = \frac{10(s^2 + 3)}{s(s^2 + 2s + 5)}. \] The final value of the signal \( x(+\infty) = \underline{\hspace{1cm}} \)
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