The Laplace transform of f(t) = e¤ cos wt is Select one: O F(s) = w/((s - a)^2 + w^2) O F(s) = (S - a)/((s - a)^2 + w^2) O F(S) = a/((s - a)^2 + w^2) O F(s) = s/((s - a)^2 + w^2)

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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The Laplace transform of f(t)
= ed cos wt is
Select one:
O F(S) = w/((s - a)^2 + w^2)
O F(s) = (s - a)/((s - a)^2 + w^2)
O F(S) = a/((s - a)^2 + w^2)
O F(s) = s/((s - a)^2 + w^2)
Transcribed Image Text:The Laplace transform of f(t) = ed cos wt is Select one: O F(S) = w/((s - a)^2 + w^2) O F(s) = (s - a)/((s - a)^2 + w^2) O F(S) = a/((s - a)^2 + w^2) O F(s) = s/((s - a)^2 + w^2)
1
2
The inverse Z-transform of the signal H(z) =
is given by
1 - 0.5 z
1 - 3z-1
Select one:
O 0.5^n u(n) - 3^n 2u(n)
O 0.5^n u(n) + 3^n 2u(n)
O 0.5^n u(n) - 3^n u(n)
O 0.5^n u(n) + 3^n u(n)
Consider a continuous signal x(t)
= cos 600 Tt + sin 800 Tt. Then the Nyquist rate for y(t) = x(2t + 5) is
Select one:
О а. 1600
O b. 1200
О с. 3200
O d. 800
Transcribed Image Text:1 2 The inverse Z-transform of the signal H(z) = is given by 1 - 0.5 z 1 - 3z-1 Select one: O 0.5^n u(n) - 3^n 2u(n) O 0.5^n u(n) + 3^n 2u(n) O 0.5^n u(n) - 3^n u(n) O 0.5^n u(n) + 3^n u(n) Consider a continuous signal x(t) = cos 600 Tt + sin 800 Tt. Then the Nyquist rate for y(t) = x(2t + 5) is Select one: О а. 1600 O b. 1200 О с. 3200 O d. 800
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