The kinetics of decomposition of N 20 5 was studied by measuring the concentration of N 20 5 as a function of time. The plot of concentration versus time is not linear, but the plot of the natural log of the concentration versus time is linear with a slope of -0.0358. What is the rate law for the decomposition?

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**Question 8**

The kinetics of decomposition of \( \text{N}_2\text{O}_5 \) was studied by measuring the concentration of \( \text{N}_2\text{O}_5 \) as a function of time. The plot of concentration versus time is not linear, but the plot of the natural log of the concentration versus time is linear with a slope of -0.0358. What is the rate law for the decomposition?

- ( ) rate = -0.0358(sec\(^{-1}\))[N\(_2\)O\(_5\)]
- ( ) rate = 0.0358(sec\(^{-1}\))[N\(_2\)O\(_5\)]
- ( ) rate = 0.0358(M\(^{-1}\)s\(^{-1}\))[N\(_2\)O\(_5\)]\(^2\)
- ( ) rate = 0.0358 M/s
Transcribed Image Text:**Question 8** The kinetics of decomposition of \( \text{N}_2\text{O}_5 \) was studied by measuring the concentration of \( \text{N}_2\text{O}_5 \) as a function of time. The plot of concentration versus time is not linear, but the plot of the natural log of the concentration versus time is linear with a slope of -0.0358. What is the rate law for the decomposition? - ( ) rate = -0.0358(sec\(^{-1}\))[N\(_2\)O\(_5\)] - ( ) rate = 0.0358(sec\(^{-1}\))[N\(_2\)O\(_5\)] - ( ) rate = 0.0358(M\(^{-1}\)s\(^{-1}\))[N\(_2\)O\(_5\)]\(^2\) - ( ) rate = 0.0358 M/s
Expert Solution
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Plot of log of concentration vs time is linear. This suggests that reaction follows first order kinetics.

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